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Rus_ich [418]
3 years ago
10

How is the definition of property similar in science and math​

Mathematics
1 answer:
sdas [7]3 years ago
6 0

Answer:

Properties in math are used as general rules to solve problems.

I hope this helped!

Step-by-step explanation:

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Identify the graph of ƒ(x) = x2 + 6x – 7 from the choices below.
torisob [31]

f(x) = x^2 + 6x - 7

y = x^2 + 6x - 7

y = (x - 1)(x + 7)

x + 7 = 0

x = -7

x - 1 = 0

x = 1

The x-intercepts are -7 and 1.

Since the leading coefficient is a positive, the graph will point upwards.

So, the graph of the function is D.

5 0
3 years ago
Each of the 25 students in Mr. McDonald’s class sold 16 raffle tickets. If each ticket costs $15, how much money did Mr. McDonal
REY [17]
So do
25x16=400
this shows how many raffle tickets were sold all together
Then do 400x$15 =$6000
So all together they raised $6000
6 0
3 years ago
Read 2 more answers
If x+3/3 = y+2/2, then x/3 =​
Kisachek [45]

Answer:

y/3

Step-by-step explanation:

x + 3/3 = y + 2/2

x + 1 = y + 1

x = y + 1 - 1

x = y + 0

x = y

so; x/3 = y/3

8 0
3 years ago
9 please help with 9 <br><br> 10 what is P
LenaWriter [7]

Answer:

9.

The probabilities are the same

10.

1/3

Step-by-step explanation:

9.

Assuming the coin is fair;

The probability of getting heads in a single toss is, P(H) = 1/2

The probability of getting tails in a single toss is, P(T) = 1/2

Now, P(H,H,H) is the probability of obtaining 3 heads in the e tosses. Since each toss is independent of the others,;

P(H,H,H) = P(H)*P(H)*P(H)

              = 1/2 * 1/2 * 1/2 = 1/8

On the other hand, P(H,T,H) is the probability of obtaining a head followed by a tail followed by a final head. Using the independence property;

P(H,T,H) = P(H)*P(T)*P(H)

              = 1/2 * 1/2 * 1/2 = 1/8

Therefore, P(H,H,H) = P(H,T,H)

10.

We are informed that a coin is tossed and a number cube is rolled. We are to determine the following probability;

P(heads, a number less than 5)

Assuming the coin is fair;

The probability of getting heads in a single toss is, P(H) = 1/2

Assuming the number cube is fair as well, the probability of rolling a number less than 5 is;

4/6 = 2/3

This is because there are 4 numbers less than 5, (1, 2, 3, 4) while the cube has 6 sides.

P(heads, a number less than 5), the events presented here are independent since the outcome from tossing the coin does not in any way determine the outcome from rolling the number cube. Therefore,;

P(heads, a number less than 5) = P(heads)*P(a number less than 5)

                                                    = 1/2 * 2/3 = 1/3

3 0
3 years ago
An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.
SCORPION-xisa [38]

Answer:

(a)See below

(b)I) 0.125  (ii)0.828125   (iii)0.234375   (iv) 0.625   (v)0.65625

Step-by-step explanation:

When an  8-sided die is rolled twice, the sample space is the set of all possible pairs (a,b) where a is the 1st outcome and b is the 2nd outcome.

The sample space is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]

<u>PART A</u>

The sample space of the product a*b of each pair forms the required possibility diagram.

This is given as:  

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

<u>PART B</u>

I) A prime number

The number of products that gives prime numbers = 8  

The probability that the product is a prime number

=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125

ii) Not a perfect square  

Number of products that results in perfect squares =11

The probability that the product is not a perfect square

=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125

iii) A multiple of 5  

Number of products that are multiples of 5=15

 The probability that the product is a multiple of 5

=\dfrac{15}{64}\\=0.234375

iv) Less than or equal to 21

Number of products which are less than or equal to 21=40

 The probability that the product less than or equal to 21

=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625

v) Divisible by 4 or 6

Number of products divisible by 4 or 6= 42

 The probability that the product is divisible by 4 or 6

=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625

8 0
3 years ago
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