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Sliva [168]
3 years ago
12

7. A wall of length 10 m was to be built across an open

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

4167 bricks

Step-by-step explanation:

We first find the amount of space the wall will occupy by multiplying the dimensions given, is that;

=10m×4m×8cm

But 8cm=0.08m

This implies that,

10m×4m×8cm

=10m×4m×0.08m

= 9.6 {m}^{3}

The dimensions of each brick that will be used is 24 cm x12 cm x 8 cm.

We calculate the space each brick will occupy

This implies;

24 cm x12 cm x 8 cm

Converting to meters we obtain

0.24m x 0.12m x 0.08m

=2.304 \times{10}^{ - 3}{m}^{3}

To get the number of bricks that will be required, we divide 9.6 meters cube by

2.304 \times  {10}^{ - 3}{m}^{3}

\implies \frac{9.6}{2.304 \times  {10}^{ - 3}} = 4166.667

Approximately, 4167 bricks will be required.

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