The difference between a mixture and a solution is that mixtures cannot be easily separated. (Choose all that apply)

A 10-foot tree casts a 17-foot shadow directly down a slope when the angle of elevation of the sun is 42o (see figure). Find \th

inna [77]

The angle of elevation of the ground is the angle between the ground and the line of sight

The angle of elevation of the ground is 30.46 degrees

<h3>How to calculate the angle of elevation</h3>

The angle of elevation is calculated using the following tangent ratio

$\tan(\theta) = \frac{10}{17}$

Evaluate the quotient

$\tan(\theta) = 0.5882$

Take the arc tan of both sides

$\theta = \tan^{-1}(0.5882)$

Using a calculator, we have:

$\theta$ = 30.46

Hence, the angle of elevation of the ground to the nearest tenth of a degree is 30.46 degrees

Read more about elevation and distance at:

brainly.com/question/7243416

6 0

2 years ago

The property taxes in a town decrease as the distance from the local elementary school increases. The greatest property taxes ar

Ann [662]

To solve this question, we will need the help of the picture attached:

1. According to this, every 101010 miles from the elementary school (Assuming the school is in point 0 of the line) the property taxes decrease 0.5%.

2. We also know that the greatest value in property taxes is 4.5%, and this decreases every 101010 miles.

So, if we draw a line divided in sections of 101010 miles and taking into account the data given, we have to sum each 101010 miles section until we get to the property tax value of the house, which is 3% in this problem.

Then, the distance from the school to the house, taking into account the 0.5% decrease with the distance is:

303030 miles

3 0

2 years ago

The authors most likely use the examples in lines 1–7

marishachu [46]

Answer:

I need you to elaborate further

3 0

2 years ago

Sam is proving the product property of logarithms. Step justification mc030-1. Jpg given mc030-2. Jpg substitution which express

harina [27]

The justification of the third step in her proof of the property of logarithms is; $log_{b} (b^{xy})$ ; Power rule of exponents

<h3>What are properties of Logarithms?</h3>

From the full question, the second step stopped at;

$log_{b} (b^{x} . b^{y} )$

Now, according to Power Rule for Exponents we know that (a^m)ⁿ = a^(m*n). That means that to raise a number with an exponent to a power, we will multiply the exponent times the power.

Thus, $log_{b} (b^{x} . b^{y} )$ will give us $log_{b} (b^{xy})$ using power rule of exponents

Read more about Properties of Logarithms at; brainly.com/question/14765705

8 0

2 years ago

Read 2 more answers

How many grams of sucrose, c12h22o11, must be added to 500. G of water at 100°c to change the vapor pressure to 752 mm hg?.

denpristay [2]

The mass number of sucrose that must be added to 500 g of water is 100.979 grams

To be able to solve this question, we need to use the number of moles concept and mole fraction concept.

<h3>What is the number of moles?</h3>

The number of moles is related to the mass of the substance divided by the molar mass of the substance.

From the given parameters;

The number of moles of water = mass/molar mass

Mass of water = 500 g
the molar mass of water = 18.02 g/mol

number of moles = 500 g/ 18.02 g/mol

number of moles = 27.75 moles

However,

the standard vapor pressure of the solvent $\mathbf{P^0_{water}}$ = 760 mmHg

the vapor pressure of the solute = 752 mmHg

Using the mole concept:

$\mathbf {X_{C_{12}H_{22}O_{11}} = \dfrac{n_{C_{12}H_{22}O_{11}}}{n_{H_2O}+n_{C_{12}H_{22}O_{11}}} }$

By relative lowering of vapor pressure:

$\mathbf{\dfrac{P^0_{H_2O} - P_{H_2O}}{P^0_{H_2O}} = X_{C_{12}H_{22}O_{11}}}$

$\mathbf{\dfrac{760 -752}{760} = \dfrac{n_{C_{12}H_{22}O_{11}}}{27.75 +n_{C_{12}H_{22}O_{11}}} }}$

$\mathbf{0.01053 = \dfrac{n_{C_{12}H_{22}O_{11}}}{27.75 +n_{C_{12}H_{22}O_{11}}} }}$

$\\ \\ \mathbf{0.01053 (27.75) +0.01053 (n_{C_{12}H_{22}O_{11}} ) = n_{C_{12}H_{22}O_{11}}}$

$\\ \\ \mathbf{0.2922075 =0.98947
 (n_{C_{12}H_{22}O_{11}} )}$

$\\ \\ \mathbf{ (n_{C_{12}H_{22}O_{11}} ) = \dfrac{0.2922075 }{0.98947}}$

$\\ \\ \mathbf{ (n_{C_{12}H_{22}O_{11}} ) =0.295 \ moles}$

The mass of sucrose = number of moles × molar mass

The mass of sucrose = 0.295 moles × 342.3 g/mol

The mass of sucrose = 100.979 grams

Learn more about number of moles here:

brainly.com/question/13314627

8 0

1 year ago