The equation would be x<5
First, graph the line x=5
Then, to determine which side of the line to shade, use a test point. I like (0,0). I plug in 0 for x because that is the x value. 0 does make the equation correct so (0,0) is included inside the shaded area. Shade the side that has (0,0) in it and you're done.
Answer/Step-by-step explanation:
3.a. length of AC.
Hypotenuse = AC
Opposite side to 60° = 7
Therefore, 
(to nearest tenth)
b. Length of BC
Hypotenuse = BC
Opposite side to 50° = 7
Therefore, 
(to nearest tenth)
c. Length of AB
Use the law of sines to find AB
m<C = 180 - (60 + 50) (sum of angles in a triangle) = 70°
m<A = 60°
BC = 9.1
AB = ?
Cross multiply
Divide both sides by sin(60)
(nearest tenth)
Answer:
PQ = 16.04cm
Step-by-step explanation:
θ = 76°
QR = 4cm
PQ = ?
Since it's a right angle triangle,
QR = adjacent
PQ = opposite
Tanθ = opposite/adjacent
Tan76 = pq / 4
PQ = 4tan76
PQ = 4 * 4.010
PQ = 16.04cm
Answer:
4+4+8+8+422+33+65520222222+222= 65,520,222,923
