The ratio of OC to OA is OC/ 10√2 - OC
<u>Explanation:</u>
Given -
AD = 4 cm
M is the midpoint of CD
Ratio of OC to OA = ?
In a square, all the interior angles are 90°
Therefore,
ΔADC, ΔABC and ΔBCM are right angled triangle
AC is the diagonal which divides ∠DAB and ∠DCB equally
If AD = 4 cm, then AB, BC and DC are also 4cm
In ΔADC,
(AC)² = (AD)² + (DC)²
(AC)² = (10)² + (10)²
AC = 10√2 cm
AC = OA + OC
OA = AC - OC
OC/OA = OC / AC - OC
OC / OA = OC / 10√2 - OC
Therefore, the ratio of OC to OA is OC/ 10√2 - OC
Answer:
<h2><em><u>
15x</u></em></h2>
Step-by-step explanation:
4x(2x+3)-5x
4x(8x+3)-5x
8x+12x-5x
8x+12x=20x
20x+-5x=15x
I really hope this helps plz let me know if its wrong! Im sorry if it is!
Answer:
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9514 1404 393
Answer:
- Proportional, y = 3 times x
- Not proportional
Step-by-step explanation:
The graph shows a proportional relationship if it is a straight line that goes through the origin (0, 0). The constant of proportionality can be found by looking for the y-value when x = 1.
1) The graph is a straight line that goes through the origin. The relationship is proportional. When x=1, y=3, so ...
y = 3 times x
__
2) The graph does not go through the origin. The relationship is Not Proportional.