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mafiozo [28]
3 years ago
15

Columbus Ohio Population: 8.23 * 10^5

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0
This is Scientific Notation here's what you have to do:

First find the Notation:

8.23×10^5

It positive so go to the right.

=823000.

Next do the same thing but with the next Notation:

3.19×10^8

Its positive so go to the right:

=319000000.

Then compare the Notation's

823000. and 319000000.

319000000. is bigger than 823000.

So your answer is 319000000. so its United States.
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M <2=x+94 what does x equal
Shtirlitz [24]
This is as far as I could get X=-94+m<2
6 0
3 years ago
How do I do this? 50 points plus brainliest.
Reil [10]

Answer:

you just gotta look at the angles, the middle letter is usually what's being focused on

17. angle QMR is less that TMS

18. angle QMR and angle TMS are supplementary angles

19. angle QMR and angle MTS are vertical angles

20. If measure angle QMT = 70 degrees, then measure angle RMS is 70 degrees because they are congruent

Step-by-step explanation:

3 0
3 years ago
a bag contains 6 black marbles and 6 white marbles. What is the least number of marbles that you must choose, without looking, t
o-na [289]

Given:

Number of black marbles = 6

Number of white marbles = 6

Let's determine the least number of marbles that can be chosen to be certain that you have chosen two marble of the same color.

To find the least number of marble to be chosen to be cartain you have chosen two marbles of the same color, we have:

Total number of marbles = 6 + 6 = 12

Number of marbles to ensure at least one black marble is chosen = 6 + 1 = 7

Number of marbles to ensure at least one white marble is chosen = 1 + 6 = 7

Therefore, the least number of marbles that you must choose, without looking , to be certain that you have chosen two marbles of the same color is 7.

ANSWER:

7

6 0
1 year ago
Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the
Alborosie

Answer:

Step-by-step explanation:

Let the subscripts d and n represent day and night respectively

The null hypothesis is

H0 : μd ≥ μn

The alternative hypothesis is

H1 : μd < μn

it is a one-tailed and also a right left test because of the greater than symbol in the alternative hypothesis.

The decision rule is to reject H0: μd ≥ μn If 0.10 > p value

Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (xd - xn)/√σd²/nd + σn²/nn

Where

xd and xn represents sample means for day and night respectively.

σd and σn represents population standard deviations for day and night respectively.

nd and nn represents number of samples

From the information given,

xd = 334

xn = 341

σd = 23

σ2 = 28

nd = 60

nn = 68

z = (334 - 341)/√23²/60 + 28²/68

= - 7/√20.34607843138

z = - 1.55

From the normal distribution table, the probability value corresponding to the z score is 0.061

Since the level of significance, 0.1 > 0.061, we would reject H0

Therefore, there is enough evidence to conclude that there are more units produced on the night shift than on the day shift.

8 0
3 years ago
Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among
Olegator [25]

Answer:

a) X[bar]₁=  1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

a)

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

b)

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

c)

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= \frac{1}{n_1-1}[∑X₁² - (( ∑X₁)²/n₁)]= \frac{1}{14} + [52829538 - (\frac{27588^{2} }{15}) = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0
3 years ago
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