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pickupchik [31]
3 years ago
15

Please who could help me

Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0
41) Circumference of a circle is 2*pi*radius, or pi*diameter.
Diameter given is 0.5cm, so circumference is 0.5pi, approximately 1.57cm.

It says scale is 1 cm to 2.5ft. Use dimensional analysis. You can multiply by 2.5ft / 1 cm because it equals 1, and multiplying by 1 doesn't change the value (just the units here).

1.57cm * 2.5ft
               -------- = 3.925ft
                1 cm
C) 4 feet

42) 6% of $900 is 0.06*$900, which is $54.

$900 is including tax, so subtract the tax ($54) to get the price before tax.
$900 - $54 = $846
A) $846
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What is the image of the point (-5,-7) after a rotation of 270 counterclockwise about the origin
Softa [21]

Answer:

Your answer will be (-5,7).

Step-by-step explanation:

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4 years ago
The mean number of people per day visiting an art show in July was 120. If 30 more people each day visited the museum in August,
Assoli18 [71]
I think it’s B I am not sure if it’s wrong sorry :(
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3 years ago
A reference sheet given with an exam indicated the following formula for the surface area of a cone.
scZoUnD [109]

Answer:

A.

Using the given formula, the calculated surface area would be in cubic units instead of square units.

Step-by-step explanation:

8 0
3 years ago
Sin(x)^4+ cos(x)^4=1/2
posledela
I'll assume that what was meant was \sin ^4 x + \cos ^4 x = \dfrac{1}{2}.

The exponent in the funny place is just an abbreviation:   \sin ^4 x = (\sin x)^4.

I hope that's what you meant. Let me know if I'm wrong.

Let's start from the old saw

\cos^2 x + \sin ^2x = 1

Squaring both sides,

(\cos^2 x + \sin ^2x)^2 = 1^2

\cos^4 x + 2 \cos ^2 x \sin ^2x +\sin ^4x = 1

\cos^4 x + \sin ^4x = 1 - 2 \cos ^2 x \sin ^2x

So now the original question 

\sin ^4 x + \cos ^4 x = \dfrac{1}{2}

becomes
1 - 2 \cos ^2 x \sin ^2x = \dfrac{1}{2}

4 \cos ^2 x \sin ^2x = 1

Now we use the sine double angle formula

\sin 2x = 2 \sin x \cos x

We square it to see

\sin^2 2x = 4\sin^2 x \cos^2 x = 1

Taking the square root,

\sin 2x = \pm 1

Not sure how you want it; we'll do it in degrees. 

When we know the sine of an angle, there's usually two angles on the unit circle that have that sine.  They're supplementary angles which add to 180^\circ.  But when the sine is 1 or -1 like it is here, we're looking at 90^\circ and -90^\circ, which are essentially their own supplements, slightly less messy. 

That means we have two equations:

\sin 2x = 1 = \sin 90^\circ

2x = 90^\circ + 360^\circ k \quad integer k

x = 45^\circ + 180^\circ k

or 


\sin 2x = -1 = \sin -90^\circ

2x = -90^\circ+ 360^\circ k

x = - 45^\circ + 180^\circ k

We can combine those for a final answer,

x = \pm 45^\circ + 180^\circ k \quad integer k

Check.  Let's just check one, how about

x=-45^\circ + 180^\circ = 135^\circ

\sin(135)= 1/\sqrt{2}

\sin ^4(135)=(1/\sqrt{2})^4 = 1/4

\cos ^4(135)=(-1/\sqrt{2})^4 = 1/4

\sin ^4(135^\circ) +\cos ^4(135^\circ) = 1/2 \quad\checkmark


6 0
3 years ago
Beth read 10 pages in a book stopping at the top of page a on what pages did she begin
Olegator [25]
She begins on page eleven
4 0
4 years ago
Read 2 more answers
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