Answer:So its simple just forget about the letters add the numbers then place the letter and x
Step-by-step explanation: ( Always Parentheses first) Then i think you divide it by the outside number
4c+3=15
You need to get rid of the 3
So you minus it from each side so you
4c=12
12/4=3
So c =3
<u>ΔACB</u> <u>ΔCDA</u>
AC² + BC² = AB² AD² + CD² = AC²
BC² = AB² - AC² BC² + CD² = AC² (AD=BC is given)
BC² = AC² - CD²
AB² - AC² = AC² - CD² (both sides were = to BC²)
AB² + CD² = 2AC²
(3)² + (√2)² = 2AC² (AB=3 and CD=√2 were given)
9 + 2 = 2AC²
11 = 2AC²
= AC²
= AC
= AC