Answer:
A basis is {v1,v4}
v2 = 3 v1 -11/3 v4
v3 = 1/3 v1 + 10/9 v4
v5 = -1/3 v4
Step-by-step explanation:
Lets triangulate the matrix that has the elements v1, v2, v3, v4 and v5 as their rows
Lets divide each row by its first element, which is possible because it is different than 0
Thus v5 = v4 / -3 = -1/3 * v4. We can take it out. Also, we will take each row except the first one and substract the value of the first row from them, obtaining
Note that now, from the second row onwards, each row is a multiple of the other. So we can remove every row except 2 of them, for example the first one and the fourth one
We can form a base of the subspace of R³ spanned by v1,v2,v3,v4,v5 with {v1,v4}. Also, we have
v5 = -1/3*v4
(v1/-2-v3/-4)*1.5 = (v1/-2-v4/-3)*1.25, hence
0.25v1/-2 + 1.25 v4/-3 = 1.5 v3/-4
Thus
v3 = -8/3 *0.25 v1/-2 - 8/3*1.25 v4/-3 = 1/3 v1 + 10/9 v4
In a similar way,
(v1/-2-v2/5)*1.5 = (v1/-2-v4/-3)*3.3
Thus
v2 = 10/3 * (-1.8v1/-2 + 3.3v4/-3) = 3 v1 -11/3 v4