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PtichkaEL [24]
3 years ago
8

x(x+3)(x+3)=0 Please I NEED HELP FAST! PLLLLLLLLLLLLLLLLLLLLLLLLLLEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

SSSSSSSSSSSSSSSSSSSSSSSSSSEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!
Mathematics
2 answers:
lesantik [10]3 years ago
5 0

\text{If   } \: a\cdot b \cdot c = 0 \text{ then } a=0 \text{ or } b =0 \text{ or }  c=0 \text{ or all of them are equal to zero.}

x(x+3)(x+3) =0

\boxed{x_1 =0}

x_2+3 =0

\boxed{x_2 = -3}

x_3+3 =0

\boxed{x_3 = -3}

ivanzaharov [21]3 years ago
3 0

Answer:

\boxed{x^3+6x^2+9x}

Step-by-step explanation:

x(x+3)(x+3)

Resolving the first parenthesis

(x^2+3x) (x+3)

Using FOIL

x^3+3x^2+3x^2+9x

Adding like terms

x^3+6x^2+9x

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Answer:

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Step-by-step explanation:

Given that:

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3 years ago
1+(-2-5)^2+(14-17)×4 please answer
hjlf
When you simplify the expression you get 38. Hope this helps.

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4 years ago
PLEASE HELP FIGURE OUT HOW TO DO THIS! THANK YOU!
S_A_V [24]
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