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2 years ago

If r(x)=3x-1 and s(x)=2x+1, which expression is equivalent to (r/s)(6)

Mathematics

1 answer:

Veseljchak [2.6K]2 years ago

7 0

Answer:

Step-by-step explanation:

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Please help This Is A Speed, Time and Distance Worksheet! Please SHOW your WORK!

Aloiza [94]

I can't help you sorry

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2 years ago

Need help asap please

Rzqust [24]

Answer:

Option 3

Step-by-step explanation:

The number on the inside is the dividend and the number on the outside is the divisor. So we just have to place the dividend on the top and the divisor on the bottom.

7 0

2 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

2 years ago

The weights of five grapefruits are 7 47 ounces, 7.23 ounces, 6.46 ounces, 7.48 ounces, and 6.81 ounces. Using the

gulaghasi [49]

Answer:

The approximate total weight of the grapefruits, using the clustering estimation technique is B. 35 ounces.

Step-by-step explanation:

We notice that the weights of the grapefruits given are slightly down or above 7, then we will use 7 as our cluster for the estimation, as follows:

Weights

7.47 ⇒ 7

7.23 ⇒ 7

6.46 ⇒ 7

7.48 ⇒ 7

6.81 ⇒ 7

Now we can add up 7 + 7 + 7 + 7 + 7 for the weights of the grapefruits and the approximate total weight is B. 35 ounces.

8 0

2 years ago

Read 2 more answers

What is the slope of the line determined by the points (5,-3) and (-9,-6)

Serggg [28]