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Pavlova-9 [17]
4 years ago
10

There are how many quarters in 2 and a half year

Mathematics
1 answer:
lisov135 [29]4 years ago
4 0

Discuss answers modelling by placing two quarters over a half to show they are the same. Show 2/4 = 1/2, 2/2 = 1 and 4/4 = 1 emphasise two halves are a whole, four quarters are a whole and two quarters are a half.

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Convert 33:19 as a percentage
satela [25.4K]

Answer:

34gh3dyh3h2tuz ext behhz

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3 years ago
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Solve for k k/2 + 1/2 = 3
Sedaia [141]

k/2+1/2=3

Move +1/2 to the other side. Sign changes from +1/2 to -1/2

k/2+1/2-1/2=3-1/2

k/2=3-1/2

Find the common denominator for 3 and -1/2.

Common denominator is 2

k/2=3(2)-1/2

k/2= 6/2-1/2

k/2=5/2

Multiply k/2 with 2. Multiply 2 with 5/2

k/2 (2/1)=2(5/2)

Cross out 2 and 2. Divide by 2. Cross out 2 and 2 for 5/2(2). Divide by 2

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4 years ago
Yellowknife Canada has a daily temperature of -18 degrees Fahrenheit. Barrow Alaska has a temperature that is 7 degrees warmer.
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Step-by-step explanation:

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3 years ago
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12). Omar has $8,274 in a savings account that earns 10.5% interest, compounded annually. To the nearest cent, how much will he
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Step-by-step explanation:

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3 years ago
Two independent samples of sizes 20 and 30 are randomly selected from two normally distributed populations. Assume that the popu
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Answer:

b. Student-t with 48 degrees of freedom

Step-by-step explanation:

For this case we need to use a Two Sample t Test: equal variances.

Assumptions

When running a two-sample equal-variance t-test, the basic assumptions are "that the distributions of the two  populations are normal, and that the variances of the two distributions are the same".

Let \bar x and \bar y be the sample means of two sets of data of size n_x and n_y respectively. We assume that the distribution's of x and y are:

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y \sim N(\mu_y ,\sigma_y=\sigma)

Both are normally distributed but without the variance equal for both populations.

The system of hypothesis can be:

Null hypothesis: \mu_x =\mu_y

Alternative hypothesis: \mu_x \neq \mu_y

We can define the following random variable:

t=\frac{(\bar x -\bar y)-(\mu_x -\mu_y)}{s\sqrt{\frac{1}{n_x}+\frac{1}{n_y}}}

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And the pooled variance can be founded with the following formula:

s^2=\frac{(n_x -1)s_x^2 +(n_y-1)s_y^2}{n_x +n_y -2}

So on this case the best answer would be :

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