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Alla [95]
3 years ago
5

Which of the following graphs are identical

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

The domain is x ≥ -7

Step-by-step explanation:

The domain asks what values can x take

We know that the sqrt(x+7) must be ≥ 0

That means the smallest value it can be is zero

x+7 ≥ 0

x ≥ -7

The domain is x ≥ -7

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Help: The equation is in the screenshot
Svetllana [295]

The graph of the function shows that function f(x) => ∞ as x = -∞ and f(x) =>-∞ as x = ∞. Option c is correct.


<h3>What is a graph?</h3>

The graph is a demonstration of curves that gives the relationship between the x and y-axis.


Here,
The curve of the function in the 2 quadrants is increasing when x tends to -∞ and in the quadrant, the curve f(x) is decreasing to -∞ as x tends to ∞.


Thus, the graph of the function shows that function f(x) => ∞ as x = -∞ and f(x) =>-∞ as x = ∞. Option c is correct.

Learn more about graphs here:

brainly.com/question/16608196

#SPJ1


8 0
2 years ago
CAN SOMEBODY PLEASE HELP? I WILL GIVE BRAINLIEST!!
IceJOKER [234]

Answer:0

Step-by-step explanation:2≠8,10 so we use the bottom formula. We get 4 - 6 + 2=0

7 0
2 years ago
Use the domain {-1, 0, 1, 2, 3, 4} and plot the points on the graph that would best satisfy the equation y = 2x.
Dmitrij [34]
Domain is ur x values

y = 2x...when x = -1
y = 2(-1)
y = -2.....(-1,2) satisfies this equation

y = 2x....when x = 0
y = 2(0)
y = 0....(0,0) satisfies it

y = 2x....when x = 1
y = 2(1)
y = 2....so (1,2) satisfies it

y = 2x....when x = 2
y = 2(2)
y = 4....(2,4) satisfies it

y = 2x...when x = 3
y = 2(3)
y = 6.....(3,6) satisfies it

y = 2x...when x = 4
y = 2(4)
y = 8.....(4,8) satisfies it
4 0
3 years ago
What is the interquartile range of this data?
jok3333 [9.3K]
Hello!

To find the interquartile range you subtract the lower quartile by the higher quartile

33 - 25 = 8

The answer is C)8

Hope this helps!
6 0
3 years ago
Please help!!!!!!!!!!!
Assoli18 [71]

<u>Let's take this problem step by step:</u>

<u>To find the ordered pair of the system:</u>

⇒ must set both equations equal to each other

    ⇒ and solve for 'x'

<u>Let's solve:</u>

 x^2-2x+3=-2x+19\\x^2-2x+2x+3-19=0\\x^2-16=0\\(x+4)(x-4)=0

<u>Let's find the x-values:</u>

   (x-4)=0\\x=4\\\\(x+4)=0\\x=-4

<u>Let's find f(x)'s value for each 'x':</u>

 x=4\\f(4)=-2(4)+19=-8+19=11\\\\x=-4\\f(-4)=-2(-4)+19=8+19=27

<u>Answer: (4, 11), (-4,27)</u>

Hope that helps!

#LearnwithBrainly

3 0
1 year ago
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