Answer:
Check the explanation
Explanation:
# Step 1
the first thing to execute will be......
f = open("states.txt")
# Step 2
the second step is......
states = []
for line in f:
states.append(line.strip())
# Step 3:
the third step is to......
for state in sorted(states):
print(state)
f.close()
Make the zig zag part more spaced out
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer:
Changing Margins
Selecting the Printer
Viewing a preview
Selecting the pages to print
Changing the page orientation
Explanation:
37 most likely.
No programming language is specified, and you didn't put what the function is, so assuming it's already implemented, MAX should display the highest number.
