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Vikentia [17]
4 years ago
10

Solve the problem x/27=4/9 x=

Mathematics
1 answer:
Monica [59]4 years ago
7 0

Answer: x=12

Step-by-step explanation:

  • Multiply both sides by 27.
  • Use this rule: a/b*c=ac/b
  • Simplify 4×27 to 108.
  • Simplify 108/9 to 12

x=\frac{4}{9} *27\\\\x=\frac{4*27}{9} \\\\x=\frac{108}{9} \\\\x=12

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

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Solve the system by using a matrix equation
Sergeu [11.5K]

Answer:

Option A is correct (17,11).

Step-by-step explanation:

6x - 9y = 3

3x - 4y =7

it can be represented in matrix form as\left[\begin{array}{cc}6&-9\\3&4\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}3\\7\end{array}\right]

A= \left[\begin{array}{cc}6&-9\\3&4\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}3\\7\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (6*-4) - (-9*3)

                                    = (-24)-(-27)

                                    = (-24) + 27 = 3

so, |A| = 3

Adj A=  \left[\begin{array}{cc}-4&9\\-3&6\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-4&9\\-3&6\end{array}\right]/3

A⁻¹ =  \left[\begin{array}{cc}-4/3&3\\-1&2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}-4/3&3\\-1&2\end{array}\right] *\left[\begin{array}{c}3\\7\end{array}\right]

X= \left[\begin{array}{c}(-4/3*3) + (3*7)\\(-1*3) + (2*7)\end{array}\right]

X= \left[\begin{array}{c}-4+21\\-3+14\end{array}\right]

X= \left[\begin{array}{c}17\\11\end{array}\right]

x= 17, y= 11

solution set= (17,11).

6 0
3 years ago
Read 2 more answers
An urn contains 12 balls, of which 4 are white.
wel

Answer:

a) \frac{1}{3}

b) \frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let A_i\,,\,B_i\,,\,C_i denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: P(A_1)=\frac{4}{12}=\frac{1}{3}

If A lost and B wins: P\left ( B_1|A_1^{c} \right )=\frac{4}{11}

If A and B lost and C wins: P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}

and so on....

4 0
4 years ago
CAN SOMEONE HELP ME WITH THIS QUESTION!!!
earnstyle [38]

Answer:

E

Step-by-step explanation:

let a, b, c represent the number of students in 6th, 7th, 8th grade

ratio of students : teachers = 28 : 1

There are 82 teachers , so 28 × 82 = 2296 students

Then

a + b + c = 2296 , that is

828 + b + c = 2296 ( subtract 828 from both sides )

b + c = 1468 → E

8 0
3 years ago
You saved 300 to spend over summer. You decide to budget 50 to spend each week. Write and equation that represents the situation
Anestetic [448]
Y=300-50x
Y= total $
X= number of weeks
5 0
3 years ago
Read 2 more answers
Can someone help plz ​
steposvetlana [31]
Subtract it and you will find your answer hope this helps
5 0
3 years ago
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