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marishachu [46]
3 years ago
9

Write an equation to express the value of h+k

Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

When written in "vertex form":
• (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.

• the h represents a horizontal shift (how far left, or right, the graph has shifted from x = 0).

• the k represents a vertical shift (how far up, or down, the graph has shifted from y = 0).

• notice that the h value is subtracted in this form, and that the k value is added.
             If the equation is y = 2(x - 1)2 + 5, the value of h is 1, and k is 5.
             If the equation is y = 3(x + 4)2 - 6, the value of h is -4, and k is -6.

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What two numbers can equal to 70 when added in 34 when subtracted.
lina2011 [118]

Answer:

18 and 52

Step-by-step explanation:

x + Y = 70

X - Y= 34 find the value of X interms of Y to find the answer:

X - Y= 34

X = 34 +Y

x + Y = 70

(34 + Y ) + Y = 70

34 + Y +Y = 70

2Y =70-34

2Y/2=36/2

Y = 18

x + 18 = 70

x=70 - 18

x= 52

check:

18 + 52= 70

52 - 18= 34

3 0
3 years ago
Find the area of the circle ​
navik [9.2K]

Answer:

The answer is 28.26

Step-by-step explanation:

A=pir^2

A=pi(3)^2

A=9pi

A=28.26

Hope this helps :D

3 0
3 years ago
Read 2 more answers
What is the solution to the equation?<br> -4 = 1<br> .<br> Enter your answer in the box.<br> X=
beks73 [17]

Step-by-step explanation:

I'm not sure about my answer

6 0
3 years ago
Rachel read 30 minutes for every 10 minutes that she spent watching television. Nicolas read 45 minutes for every 15 minutes tha
stich3 [128]

Answer:

B.different

Step-by-step explanation:

Rachel read 30 minutes for every 10 minutes that she spent watching television

30 - 10 = 20

Nicolas read 45 minutes for every 15 minutes that he watched television

45 - 15 = 30

Hope It Helps Friend :)

4 0
3 years ago
What is the derivative of ln(lnx^3)
chubhunter [2.5K]

the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , ln(lnx^3) , Let's differentiate it w.r.t x :

⇒ \frac{d(ln(lnx^3))}{dx}

Let lnx^3 = u

⇒ \frac{d(ln(u))}{dx}

⇒ \frac{1}{u} (\frac{d(u)}{dx} )

⇒ \frac{1}{u} (\frac{d(ln(x^3))}{dx} )

Let x^3=v

⇒ \frac{1}{u} (\frac{d(ln(v))}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )            

⇒ 3x^2(\frac{1}{u})(\frac{1}{v} )

Putting value of u & v we get:

⇒ 3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )

⇒ \frac{3}{x(lnx^3)}    { lnx^n = n(lnx)  }

⇒ \frac{3}{3x(lnx)}

⇒ \frac{1}{x(lnx)}

Therefore , the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

6 0
3 years ago
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