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xz_007 [3.2K]
4 years ago
6

Anne has 8 unmarked computer disks in a​ box, where each is dedicated to exactly one of English​, Spanish​, Mathematics, compute

r science, biology​, SAT preparation, college applications, and American history. If she chooses a computer disk at​ random, what is the probability that she chooses the SAT preparation disk?
Mathematics
1 answer:
slavikrds [6]4 years ago
3 0

Answer:

The correct answer is 0.125.

Step-by-step explanation:

Anne has 8 unmarked computer disks in a​ box, namely one of English​, Spanish​, Mathematics, computer science, biology​, SAT preparation, college applications, and American history.

Let the experiment be to pick up the SAT preparation disk from this set of 8 disk

Possible outcome is only one as there is only one SAT preparation disk.

Total number of outcomes, i.e. total number of disks available is 8.

Probability of picking of SAT preparation disk is

Probability = \frac{possible outcomes}{All outcomes} =  \frac{1}{8}.

You might be interested in
Evaluate.<br> 18.65 -52/11=
professor190 [17]
The answer is about 13.9927.

You would divide 52/11 and then subtract that decimal by 18.65.

18.65-4.7272=13.9927.
6 0
4 years ago
given the following information, determine which lines, if any, are parallel. state the converse that justifies your answer.
frozen [14]

From the information in the diagram found in a similar question online (please see attached drawing), the parallel lines are;

  1. w||z
  2. x||y
  3. x||y
  4. w||z
  5. w||z
  6. x||y
  7. x||y
  8. w||z
  9. x||y
  10. w||z

<h3>What are the relationships between angles formed by parallel lines?</h3>

Parallel lines are lines that do not meet, when extended indefinitely.

The possible information given as obtained from a similar question posted online are;

1. ‹1 is congruent to ‹5

2. ‹7 is congruent to ‹9

3. m‹8 + m‹9 = 180°

4. ‹16 is congruent to ‹14

5. m‹1 + m‹4 = 180°

6. ‹3 is congruent to ‹13

7. ‹2 is congruent to ‹10

8. ‹11 is congruent to ‹15

9. m‹4 + m‹13 = 180°

10. ‹8 is congruent to ‹6

1. Given that ‹1 is congruent to ‹5 where ‹1 and ‹5 are alternate exterior angles, we have that line <em>w </em>is parallel to line <em>z </em>

  • w||z

Theorem (converse); Alternate exterior angles formed by two parallel lines having a common transversal are congruent.

2. ‹7 and ‹9 are alternate interior angles.

Given that ‹7 is congruent to ‹9, therefore;

Line <em>x</em> is parallel to line <em>y</em>

  • x||y

Theorem (converse); Alternate interior angles formed by two parallel lines having a common transversal are congruent.

3. Given that m‹8 + m‹9 = 180°, therefore;

‹8 and ‹9 are supplementary angles, formed between lines <em>x </em>and <em>y</em>.

‹8 and ‹9 are also consecutive interior angles.

Theorem (converse); Consecutive interior angles formed between parallel lines are supplementary.

Therefore;

  • x||y

4. ‹16 and ‹14 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Corresponding angles formed by parallel lines are congruent.

Given ‹16 congruent to ‹14, we have;

  • w||z

5. m‹1 and m‹4 are consecutive exterior angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Consecutive exterior angles formed by two parallel lines are supplementary.

Given that m‹1 + m‹4 = 180°, we have;

  • w||z

6. ‹3 and ‹13 are alternate exterior angles formed by lines <em>x </em>and <em>y</em>.

Theorem (converse); Alternate exterior angles formed by parallel lines are congruent.

Given that ‹3 congruent to ‹13, we have;

  • x||y

7. ‹2 and ‹10 are corresponding angles formed by lines <em>x </em>and <em>y</em>

Given that ‹2 congruent to ‹10, therefore;

  • x||y

8. ‹11 and ‹15 are alternate interior angles formed by lines <em>w </em>and <em>z</em>.

‹11 is congruent to ‹15, therefore;

  • w||z

9. ‹4 and ‹13 are consecutive exterior angles formed by lines <em>x </em>and <em>y</em>

m‹4 + m‹13 = 180°, therefore;

  • x||y

10. ‹8 and ‹6 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

‹8 is congruent to ‹6, therefore;

  • w||z

Learn more about angles formed by parallel lines that have a common transversal here:

brainly.com/question/24607467

#SPJ1

3 0
1 year ago
How should we prove this ?<br> Boc=90-1/2angle bac
Hatshy [7]

We have m(<CBO) = (1/2) · m(<CBE) = (1/2) · ( x + z );

In the same way, m(<BCO) = (1/2) ·( x + y);

m(<BOC) = 180 - [(1/2) · ( x + z ) + (1/2) ·( x + y)] = 180 - (1/2)· ( x + x + y + z );

But, x + y + z = 180;

Then, m(<BOC) = 180 - (1/2)·( x + 180 );

Finally, m(<BOC) = 90 - (1/2)·x;

So, m(<BOC) = 90 - (1/2)·m(<BAC).

8 0
3 years ago
Do someone mind helping me pls :)
Whitepunk [10]
<h3>Answer:  983,700,000</h3>

=========================================================

Explanation:

The uppercase E represents "ten to the"

So saying E8 means "ten to the 8th power"

In other words, 9.837 E 8 = 9.837 * 10^8

The exponent positive 8 tells us to move the decimal point over to the right 8 spots.

So that's how we go from 9.837 * 10^8 to 983,700,000

There are 5 zeros in that value after the "9837" portion.

When we move from 9.837 to 9837.0, that's exactly 3 spots so far. Then the decimal point has to move another 5 spots to go from 9837.0 to 983,700,000 which is therefore 3+5 = 8 total shifts to the right.

The number 983,700,000 is slightly over 983 million. If anything, it's more closer to 984 million.

3 0
3 years ago
Read 2 more answers
Use the box method to distribute and simplify (5x – 6)(x^2 – x– 3). Drag and
mina [271]

Answer:

The result will be: 5x³ -11x² -9x + 18

7 0
2 years ago
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