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Bess [88]
2 years ago
6

What is the absolute value of 8/9

Mathematics
1 answer:
lions [1.4K]2 years ago
7 0
The absolute value would be 8/9.
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Ainat [17]

Answer:

I think the answer would be ⅖

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2 years ago
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Solve 2|3x-4|+4=12 show your work
slamgirl [31]

Answer:

0.6

Step-by-step explanation:

2×3x+4+4=12

6X+8=12

6x=12-8

6x=4

Divide by 6

X=0.6

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2 years ago
Find the value of g(x)=2-x^2 and f(x)=2x-1 . f(-4)
Ivenika [448]

Answer:

f(-4) = -9

Step-by-step explanation:

f(x)=2x-1

Let x = -4

f(-4)=2*-4-1

      = -8 -1

      = -9

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3 years ago
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A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

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2 years ago
Simplify the following expression. Write the result using positive exponents only. Assume that all bases are not equal to 0.
Levart [38]
Photo math is ya bestfriend
1/ x^40y^45
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