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xxTIMURxx [149]
4 years ago
6

What number is 1 hundreds 2 tens 18 ones

Mathematics
2 answers:
andrew-mc [135]4 years ago
8 0
The number is 138. Hopefully this helped.
Gemiola [76]4 years ago
8 0
100 + 20 + 18= 138 the answer is 138
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The water pressure on Mustafa as he dives is increasing at a rate of 0.9920.9920, point, 992 atmospheres (\text{atm})(atm)left p
Paha777 [63]
This problem is a simple dimensional analysis. We are simply tasked to express the rate 0.992 atm/m to atm/km.

Dimensional analysis, in simpler terms, is just the process of expressing an answer in another unit by multiplying conversion factors.

For this problem, we'll need to perform the following:

\frac{0.992 atm}{m}= \frac{1000m}{1km} = \frac{992atm}{km}

Notice that we used the conversion factor 1000 meters = 1 kilometer to convert the units from atm/m to atm/km. Thus, we arrive at the final answer 992 atm/km.
8 0
3 years ago
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The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.
Tanya [424]

The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

  • The mean is-

\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5

  • The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

  • The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

  • The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

r=97-41\\r=56

  • The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

IQR=63-23\\IQR=20

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

brainly.com/question/14532771

#SPJ1

4 0
2 years ago
What is 7/8<br> expressed as a percent?<br> Enter your answer in the box.
Alex
87.5% is the answer to your question
8 0
4 years ago
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The basic ratio for 24:56
kogti [31]
24:56 = 3:7
You can simplify it by dividing with 2 
5 0
4 years ago
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Subtract 52.35 − 1.58 = <br><br> (5 points)
Scorpion4ik [409]
Answer: 50.77
It says I need more characters, so I’m adding this
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3 years ago
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