<span>A) Joey used 10 congruent triangles to create a regular decagon.
What kind of triangles is he using?
He is using isosceles triangles. because the two sides (of each triangle) whose vertix is at the center of the decagon are congruent, while the third side, is different.
b)Joey used 10 congruent triangles to create a regular decagon.
Find the three angle measures of one of the triangles. Explain how you know.
The angle between the two congruent sides is equal to 360° divided by the number of triangles.
360° / 10 = 36.
The other two angles are congruent and must obey the rule of 180°.
2x + 36 = 180 => 2x = 180 - 36 = 144
x = 144 / 2 = 72°
Then two angles are 72° and the other is 36°.
c)Joey used 10 congruent triangles to create a regular decagon.
If the area of each triangle is 14.5 square inches, then what is the area of the regular decagon? Show all work.
The area of the decagon is ten times the area of a triangle.
Area of the decagon = 10 * 14.5 in^2 = 145 in^2.
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based on the given area for the six habitats, Dullinger and his colleagues can find the p-value to be 0.0018.
<h3>how can the p-value be found?</h3>
a chi-squared test is the best test for to find the p-value and when the data given is put through a chi-square model, the observed values are:
= 7, 9, 2, 11, 2, 0
the expected values should be:
= 1/6, 1/6, 1/6, 1/6, 1/6, 1/6
the p-value will be 0.001819
df = 5
find out more on p-value at brainly.com/question/13786078.
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solution;
a) From the given information,
N = 53,min=42 and max = 129
K = 1+3.322log₁₀53
= 1+3.322(1.724)
= 1+5.728
= 6.728
Number of classes is 7.
b) find the width of the class interval first
width = max – min /classes
= 129-42/7
= 87/7 =12.42
Take the next largest number 13 as class width. Since the minimum value is 42
The lower limit iof the first class could be 40.
So,
The upper limit of the last class is,
40+(13 x 7) = 131
As the upper limit of the last class covers the entire range of values,
It is better to take the lower limit of the first class as 40
The lower limit of the first calss could be 40.
1456 thank you and that’s your answer
Honestly don’t know am really sorry