Question

For the first five legs of a bicycle race, Elena was 32 second,5 second,10 seconds, 8 seconds, and 12 seconds behind the leader. What was the average time she was behind the leader?

Answer 1

Answer: Hello there!

if you have n numbers, x₁, x₂, .... , xₙ

The mean or average of this numbers is X = (x₁ + x₂ + ..... + xₙ)/n

now in this problem we have 5 numbers: 32s, 5s, 10s, 8s and 12s

then the mean of these numbers is:

$X = \frac{32s+ 5s +10s+8s+12s}{5} = \frac{57s}{5} = 11.4s$

The average time (per leap) that she was behind the leader is 11.4 seconds.

Answer 2

1 minute and 10 seconds (70seconds in total)