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saw5 [17]
3 years ago
7

For the first five legs of a bicycle race, Elena was 32 second,5 second,10 seconds, 8 seconds, and 12 seconds behind the leader.

What was the average time she was behind the leader?
Mathematics
2 answers:
slavikrds [6]3 years ago
8 0

Answer: Hello there!

if you have n numbers, x₁, x₂, .... , xₙ

The mean or average of this numbers is X = (x₁ + x₂ + ..... + xₙ)/n

now in this problem we have 5 numbers: 32s, 5s, 10s, 8s and 12s

then the mean of these numbers is:

X = \frac{32s+ 5s +10s+8s+12s}{5} = \frac{57s}{5} = 11.4s

The average time (per leap) that she was behind the leader is 11.4 seconds.

Helga [31]3 years ago
3 0
1 minute and 10 seconds (70seconds in total)
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