3 years ago

What the answer to 6q-1=-q+20

1 answer:

8 0

If you add q to both sides, you'll end up with 7q and the q itself would cross out. So, you're left with 7q-1=20, add the one and you have 7q=21... 21/7= 3... q=3

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3 years ago

- Use the unit circle to evaluate<br> the six trigonometric functions<br> of theta= 4pi

Helen [10]

<h2> The six trigonometric functions, $\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\tan \dfrac{\pi}{4} =1$ , $\cot \dfrac{\pi}{4} =1$ , $\sec \dfrac{\pi}{4} =\sqrt{2}$ and $\csc \dfrac{\pi}{4} =\sqrt{2}$ .</h2>

Step-by-step explanation:

We have,

$\dfrac{\pi}{4}$

To write the six trigonometric functions = ?

$\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$

$\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$

$\tan \dfrac{\pi}{4} =1$

$\cot \dfrac{\pi}{4} =1$

$\sec \dfrac{\pi}{4} =\sqrt{2}$

$\csc \dfrac{\pi}{4} =\sqrt{2}$

∴ The six trigonometric functions, $\sin \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\cos \dfrac{\pi}{4} =\dfrac{1}{\sqrt{2}}$ , $\tan \dfrac{\pi}{4} =1$ , $\cot \dfrac{\pi}{4} =1$ , $\sec \dfrac{\pi}{4} =\sqrt{2}$ and $\csc \dfrac{\pi}{4} =\sqrt{2}$ .