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shtirl [24]
3 years ago
7

How many games would Chase have to win in a row in order to have a 75% winning record?

Mathematics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

the answer is that he would have to win 7 games in a row to get 75%

Step-by-step explanation:

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The horizontal cross-sectional shapes of the prism given below are all
Genrish500 [490]
It is true that is the
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2 years ago
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An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
seraphim [82]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean compression strength from the extra carbonation of strawberry drink and μ2 be the mean compression strength from the extra carbonation of cola.

The random variable is μ1 - μ2 = difference in the mean compression strength from the extra carbonation of strawberry drink and the mean compression strength from the extra carbonation of cola.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

This is a left tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 530

x2 = 553

s1 = 23

s2 = 16

n1 = 10

n2 = 10

t = (530 - 533)/√(23²/10 + 16²/10)

t = - 2.6

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [23²/10 + 16²/10]²/[(1/10 - 1)(23²/10)² + (1/10 - 1)(16²/10)²] = 6162.25/383.752

df = 16

We would determine the probability value from the t test calculator. It becomes

p value = 0.0097

Since alpha, 0.05 > than the p value, 0.0097, then we would reject the null hypothesis. Therefore, at 5% significance level, the data suggests that the extra carbonation of cola results in a higher average compression strength.

4 0
3 years ago
Idk if my answer is right pls help will give like and brainliest
Arlecino [84]

Answer:

Yes that would be correct!

Step-by-step explanation:

You need 5a and 34 are needed in the equation and so is the x symbol

6 0
3 years ago
Read 2 more answers
Help Dana find the sum 346 421 152
chubhunter [2.5K]
To add and get the sum 
  346   
  421
+152

We start on the ones place 6 + 1 + 2 = 9, the sum of the digits in the ones place is not up to 10, we will not regroup this ones place.

So, basically the answer to 13a is NO.
Since we are not able to regroup the ones place there is no regrouped tens to add, therefore the answer to 13b is also NO.

Next is the tens place, 4 +2 +5 = 11, the sum of the digits in the ones place is up to 10 so we regroup the tens place.

Thus, the answer to 13c is YES.

Since, we regrouped the ones place, we add the regrouped hundred, thus the answer to 13d is YES.

Finally, for the hundred place, 1 + 3 + 4 + 1 = 9

Therefore, the sum of 
    346
    421
+  152
is 919
8 0
3 years ago
HURRY NEED HELP <br> I WILL MARK BRAINLIEST
Hunter-Best [27]
B can i please have brainliest
6 0
3 years ago
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