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shtirl [24]
4 years ago
7

How many games would Chase have to win in a row in order to have a 75% winning record?

Mathematics
1 answer:
morpeh [17]4 years ago
3 0

Answer:

the answer is that he would have to win 7 games in a row to get 75%

Step-by-step explanation:

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The organizers of a carnival need to buy a total of 200 small and large signs combined for the event. If the small signs cost $5
pochemuha

Answer:25$

Step-by-step explanation:

8 0
3 years ago
How many dollars are in Fifty pennies
andrew11 [14]
1/2. 50 pennies equals $0.50
4 0
3 years ago
Read 2 more answers
Someone help me please. I don't just want the answer, I need an explanation on how it's done too.​
NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j)  a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

4 0
3 years ago
4/10x - 2x + 8/5 = 4/5
mamaluj [8]

\large\displaystyle\text{$\begin{gathered}\sf \left(\frac{4}{10}\times x\right)-(2 \times x)+\frac{8}{5}=\frac{4}{5}    \end{gathered}$}

Reduce the fraction 4/10, to its minimum expression, extracting and canceling 2.

  • \large\displaystyle\text{$\begin{gathered}\sf \frac{2}{5}x-2x+\frac{8}{5}=\frac{4}{5}    \end{gathered}$}

Combine \bf{\frac{2}{5}x } and -2x to get \bf{-\frac{8}{5}x}.

  • \large\displaystyle\text{$\begin{gathered}\sf -\frac{8}{5}x+\frac{8}{5}=\frac{4}{5} \     \end{gathered}$}

Subtract 8/5 from both sides.

  • \large\displaystyle\text{$\begin{gathered}\sf -\frac{8}{5}x=\frac{4}{5}-\frac{8}{5} \ \    \end{gathered}$}

Since 4/5 and 5/8 have the same denominator, join their numerators to subtract them.

  • \large\displaystyle\text{$\begin{gathered}\sf -\frac{8}{5}x=\frac{4-8}{5}   \end{gathered}$}

Subtract 8 from 4 to get -4.

  • \large\displaystyle\text{$\begin{gathered}\sf -\frac{8}{5}x=-\frac{4}{5}   \end{gathered}$}

Multiply both sides by \bf{-\frac{5}{8}}, the reciprocal of \bf{-\frac{5}{8}}.

  • \large\displaystyle\text{$\begin{gathered}\sf x=-\frac{4}{5}\left(-\frac{5}{8}\right)   \end{gathered}$}

Multiply -4/5 by -5/8 (to do this, multiply the numerator by the numerator and the denominator by the denominator).

  • \large\displaystyle\text{$\begin{gathered}\sf x=\frac{-4(-5)}{5\times8} \ \to \ \ Multiply  \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf x=\frac{20}{40}  \end{gathered}$}

Reduce the fraction 20/40 to its lowest expression by extracting and canceling 20.

  • \boxed{\large\displaystyle\text{$\begin{gathered}\sf x=\frac{1}{2}  \end{gathered}$}}

  • <u>Good luck in your studies</u>
3 0
2 years ago
How do you solve this
loris [4]
Using the edge lengths already given, I calculated the height of the right side of the irregular octagon by adding the heights on the left. Since they added to 9m, then I put 9 on the edge with a missing height. To find the missing length, I subtracted the quantity of 6+6 from 18 (you can also divide 18 by 3) to get 6. Now that I know all the lengths, I can add them to get the perimeter. Since 3+3+3+6+6+6+9+18, or (3*3)+(6*3)+9+18 is equal to 54, our answer is 54.
7 0
3 years ago
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