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3 years ago

HELP ASAP PLEASE!!!!!!!!

Mathematics

2 answers:

Mandarinka [93]3 years ago

5 0

Answer:

Equilateral and Isosceles

tangare [24]3 years ago

4 0

Answer:

2nd one and the 3rd one not the first

Step-by-step explanation:

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TEA [102]

Answer:

angle BAC = angle DAC it is correct answer of this question ....

plz mark my answer as brainlist plzzzz vote me also so

8 0

3 years ago

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Anna007 [38]

You want to find the time t such that

$\$1000 = \$200 e^{0.04t}$

Divide both sides by $200 :

$\dfrac{\$1000}{\$200} = 5 = e^{0.04t}$

Take the logarithm of both sides:

$\ln(5) = \ln(e^{0.04t}) = 0.04t\ln(e) = 0.04t$

Divide both sides by 0.04 and solve for t :

$t = \dfrac{\ln(5)}{0.04} \approx 40.24 \approx \boxed{40}$

6 0

3 years ago

10. A weight hangs on a spring. The vibration period of that weight is the time in which it makes a complete cycle in motion. Su

Alenkinab [10]

The vibration period of the spring will be 0.2 seconds

Explanation

The relationship between the vibration period "T" (in seconds) and the weight "w" (in kilograms) is given by...

$T= 2\sqrt{\frac{w}{200}}$

Given that, the weight(w) = 2.0 kilograms

So, plugging w = 2.0 into the above equation, we will get...

$T= 2\sqrt{\frac{2.0}{200} } \\ \\ T= 2\sqrt{\frac{1}{100} }\\ \\ T= 2*\frac{1}{10}\\ \\ T= \frac{1}{5}=0.2$

So, the vibration period of the spring will be 0.2 seconds.

8 0

4 years ago

Yall I’m actually going to cry I’m having trouble understanding this please helpp please

Lelechka [254]

Answer:

I was gonna help you, but no one didn''t help meeeeeee and i am cryinggggg!!!!

Step-by-step explanation:

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3 years ago

The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of 45 mph. At what rate

Zinaida [17]

The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of 45 mph. At what rate must she return if the total travel time is three hours and forty minutes?

1st leg DATA:
distance = 90 mi ; rate = 45 mph ; time = d/r = 2 hrs.
2nd leg DATA:
distance = 90 mi ; time = [3 2/3 - 2] = 1 2/3 hrs; rate = 90/(5/3) = 54 mph
Ans: 54 mph

5 0

3 years ago

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