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3 years ago

Give any two rational number between _1/2 and _1/5.

Mathematics

2 answers:

Vaselesa [24]3 years ago

8 0

Some rational numbers are : 5/16 and 6/18

krok68 [10]3 years ago

4 0

what numbers are betwwen 2 and 5? ......<em> 3 and 4</em>

$\frac{1}{3}$ and $\frac{1}{4}$

You can check this by converting them into decimals.

$\frac{1}{2}$ = .50

$\frac{1}{3}$ = .33

$\frac{1}{4}$ = .25

$\frac{1}{5}$ = .20

Answer: $\frac{1}{3}$ and $\frac{1}{4}$

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The sum of two consecutive integers is -133 find the integers

Bess [88]

-133/2=-66.5

If we take the upper and lower round of that number we will get the 2 consecutive numbers that make -133.
Therefore the answer is -66 & -67.

8 0

3 years ago

Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0

erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

$15x^2-kx+1=0$ (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

$2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8$

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

$15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}$

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0

4 years ago

Can someone please help me?

Luda [366]

Answer:

(x-1)^5 (x+1)

Step-by-step explanation:

2 (x-1)^5 + (x-1)^6

Factor out (x-1)^5

2 (x-1)^5 + (x-1)^5 (x-1)

(x-1)^5( 2 + x-1)

Combine like terms

(x-1)^5 (x+1)

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3 years ago

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Find the zeros of y=x^3-x^2-9x+9

notsponge [240]

The zeros are at -3, 1 and 3

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3 years ago

Which of the following are not polyhedrons?

Goshia [24]

Answer:C and D

Step-by-step explanation: Hope this helps

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2 years ago