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aliya0001 [1]
3 years ago
15

Plzzz help im timedbiejsjsjdj

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

It means that the number 7 is equal to 7, so the system of equetions when simplify with the statement shows is just the equality of the number.

Step-by-step explanation:

If you read it slow you will get it

You might be interested in
3, 265 pounds is how many ounces? ​
Bad White [126]

Answer:

52,240 oz

Step-by-step explanation:

1 lb = 16oz

3,265×16=52,240 oz

4 0
3 years ago
Read 2 more answers
What is the length of ST?​
defon

Answer:

5 cm

Step-by-step explanation:

Let's assume this is a number line were given.

Distance of S from 0 = 4 units

Distance of T from 0 = 9 units

Length of ST = the difference between T and S

ST = |9 - 4| = 5 units = 5 cm

This means S and T are 5 cm apart.

3 0
3 years ago
Sami's bank account earns 4% simple interest per year. If Sami deposits $500, how much simple interest will she earn in four yea
Oksanka [162]

Answer:

20

Step-by-step explanation:

1% of 500 is 5

5*4(amount of years) = £20

3 0
2 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
I only need help on number 8 please
Setler [38]

Answer:

A y =

1

2

x − 6

Step-by-step explanation:

3 0
2 years ago
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