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elena-14-01-66 [18.8K]
3 years ago
10

Plz help me with this

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:  \bold{b)\quad \dfrac{-\sqrt{13}-5}{4}}

<u>Step-by-step explanation:</u>

\dfrac{3}{\sqrt{13}-5}\bigg(\dfrac{\sqrt{13}+5}{\sqrt{13}+5}\bigg)\\\\\\=\dfrac{3(\sqrt{13}+5)}{13-25}\\\\\\=\dfrac{3(\sqrt{13}+5)}{-12}\\\\\\=\dfrac{\sqrt{13}+5}{-4}\\\\\\=\dfrac{-\sqrt{13}-5}{4}

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