2 years ago

Plz help me with this

Mathematics

1 answer:

Jlenok [28]2 years ago

6 0

Answer: $\bold{b)\quad \dfrac{-\sqrt{13}-5}{4}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{\sqrt{13}-5}\bigg(\dfrac{\sqrt{13}+5}{\sqrt{13}+5}\bigg)\\\\\\=\dfrac{3(\sqrt{13}+5)}{13-25}\\\\\\=\dfrac{3(\sqrt{13}+5)}{-12}\\\\\\=\dfrac{\sqrt{13}+5}{-4}\\\\\\=\dfrac{-\sqrt{13}-5}{4}$

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