Answer:
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Looking at the image I have attached (with MN being the midsegment of the trapezoid), For any PQ with P and Q lying on the bases of the trapezoid there exists ON with O being the point of intersection between PQ and MN. ON must be parallel to PC because ON is part of MN and PC is a part of DC, and MN and DC are parallel. And N must be the midpoint of CB because MN is the midsegment of the trapezoid, so MN must bisect CB. And since ON is parallel to PC and bisects CB, that means it is a midsegment of QBCP and must bisect PQ.
Answer:
0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Playing at an NCAA college.
Event B: Being drafted by the MLB.
6.9% will play in an NCAA college
This means that 
8.6% of the college players will go on to be drafted by the MLB.
This means that 
What is the probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB?



0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB