Yo please take the full picture the question is cut off
Answer:
Part One: $187
Part Two: 11a + 5.5k
Step-by-step explanation:
Part One:
a = 9 (how many adult tickets)
k = 16 (how many kid tickets)
($11 × a) + ($5.50 × k) = total cost
($11 × 9) + ($5.50 × 16)
($99) + ($88) = $187 = total cost
Part Two:
11a + 5.5k
11 is how much the adult ticket costs, you multiply a or the amount of adult tickets in order to get the total cost for adults.
5.5 is how much the kid ticket costs, you multiply k or the amount of kid tickets in order to get the total cost for kids.
you add 11a + 5.5k or the total cost for adults and the total cost for kids to get the total cost.
Answer:
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- <u>No. You would have to cut the number of veggie burgers in more than half.</u>
Explanation:
<u>1. Model the situation with a system of equations</u>
<u />
<u>a) Name the variables:</u>
- number of turkey burgers: t
- number of veggie burgers: v
<u />
<u>b) Number of burgers:</u>
<u />
<u>c) Cost of the 50 burgers:</u>
<u>2. Solve that system of equations:</u>
<u />
<u>a) System</u>
<u>b) Mutliply the first equation by 2 and subtract the second equation</u>
- 100 = 2t + 2v
- 90 = 2t + 1.50v
- v = 20 ⇒ t = 50 - 20 = 30
<u />
<u>c) How much would you spend if the next year you buy the double of 20 turkey burgers (40) and the half of 30 veggie burgers (15)</u>
- $2(40) + $1.50(15) = $80 + $22.50 = $102.50
Then, you if you double the number of turkey burgers, and cut the number burgers in half, you would spend more than $90 ($102.50).
Answer:
Answer: There is no relationship between hours spent cycling and hours spent playing football. I did flvs and I got this question correct.
Step-by-step explanation:
Answer:
The confidence level is 95% or 0.95.
Step-by-step explanation:
Consider the provided information.
Results of a poll stated that 40% of U.S.
If you want to test the claim at alpha = 0.05.
As we know:
Confidence level = 1 - significance level (
)
Confidence level = 
Confidence level = 
Therefore, the confidence level is 95% or 0.95.
