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Marrrta [24]
3 years ago
7

JKLM Is a parallelogram?

Mathematics
2 answers:
mafiozo [28]3 years ago
7 0
Yes because there is 4 sides
rewona [7]3 years ago
6 0
Yes JKLM would be a parallelogram.
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How can (4x⁵/2x²)³ be solved in 2 different ways
Margaret [11]

We assume that we need to simplify the expression in two different ways.

Answer:

One way: Raise both, the numerator and denominator, to the third power, and then simplify the expression.

Second way: Simplify the terms inside parentheses, and then raise the result to the third power.

The result of both ways is the same: \\8x^{9}

Step-by-step explanation:

<em>One way</em>

Raise both, the numerator and denominator, to the third power, and then simplify the expression:

\\ (\frac{4x^{5}}{2x^{2}})^{3}

\\ (\frac{64x^{5*3}}{8x^{2*3}})

\\ (\frac{64x^{15}}{8x^{6}})

\\ \frac{64}{8}\frac{x^{15}}{x^{6}}

\\8x^{9}

This is the first simplification.

<em>Second way</em>

Simplify the terms inside parentheses, and then raise the result to the third power.

\\ (\frac{4x^{5}}{2x^{2}})^{3}

\\ (\frac{4}{2}*\frac{x^{5}}{x^{2}})^{3}

\\ (2*x^{5-2})^{3}

\\ (2*x^{3})^{3}

\\ (2^{3}*x^{3*3})

\\ (8*x^{9})

or \\ 8x^{9}.

3 0
3 years ago
1.5x-6=9 what is the number for x​
Svet_ta [14]

Answer:

x=10

Step-by-step explanation:

1.5x-6=9

     +6  +6

1.5x=15

/1.5    /1.5

x=10

5 0
4 years ago
Read 2 more answers
the graph below shows the relationship between dithering distances a delivery truck is driven and the amount of gas the truck us
LiRa [457]

Answer:

10

Step-by-step explanation:

Look at where the one gallon gas is, it's point comes to ten. :)

4 0
3 years ago
The formula for the surface area of a sphere is a 4πr2where r is the length of the radius. find the surface area of a sphere wit
o-na [289]
4(22/7)(14)^2
4(22/7)(196)
Surface area is 2464 *rounded*
4 0
4 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
4 years ago
Read 2 more answers
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