Experimental methods involve the manipulation and control of variables, whereas non experimental methods require simple observation of the variables.
Answer: Option D.
<u>Explanation:</u>
Non-experimental research about doesn't mean nonscientific. Non-experimental investigate implies there is an indicator variable or gathering of subjects that can't be controlled by the experimenter. Test plan, then again, takes into consideration specialists to control the indicator variable and subjects.
Non experimental research falls into three broad categories: single-variable research, correlational and quasi-experimental research, and qualitative research.
![\boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}](https://tex.z-dn.net/?f=%5Cboxed%7Bx_%7B1%7D%3D-15%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7Bx_%7B2%7D%3D-17%7D)
<h2>
Explanation:</h2>
In this case, we have the following equation:
![x^2+32x+256=1](https://tex.z-dn.net/?f=x%5E2%2B32x%2B256%3D1)
But we can write this equation as:
![x^2+32x+256=1 \\ \\ Subtract \ -1 \ from\ both \ sides: \\ \\ x^2+32x+256-1=1-1 \\ \\ x^2+32x+255=0](https://tex.z-dn.net/?f=x%5E2%2B32x%2B256%3D1%20%5C%5C%20%5C%5C%20Subtract%20%5C%20-1%20%5C%20from%5C%20both%20%5C%20sides%3A%20%5C%5C%20%5C%5C%20x%5E2%2B32x%2B256-1%3D1-1%20%5C%5C%20%5C%5C%20x%5E2%2B32x%2B255%3D0)
So this final result is a quadratic equation written in Standard Form (
). We need to find the solutions to this equations, so let's use quadratic formula:
![x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ b=32 \\ c=255 \\ \\ \\ x=\frac{-32 \pm \sqrt{(32)^2-4(1)(255)}}{2(1)} \\ \\ x=\frac{-32 \pm \sqrt{1024-1020}}{2} \\ \\ x=\frac{-32 \pm \sqrt{4}}{2} \\ \\ x=\frac{-32 \pm 2}{2} \\ \\ Finally, \ two \ solutions: \\ \\ \boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20%5C%5C%20a%3D1%20%5C%5C%20b%3D32%20%5C%5C%20c%3D255%20%5C%5C%20%5C%5C%20%5C%5C%20x%3D%5Cfrac%7B-32%20%5Cpm%20%5Csqrt%7B%2832%29%5E2-4%281%29%28255%29%7D%7D%7B2%281%29%7D%20%5C%5C%20%5C%5C%20x%3D%5Cfrac%7B-32%20%5Cpm%20%5Csqrt%7B1024-1020%7D%7D%7B2%7D%20%5C%5C%20%5C%5C%20x%3D%5Cfrac%7B-32%20%5Cpm%20%5Csqrt%7B4%7D%7D%7B2%7D%20%5C%5C%20%5C%5C%20x%3D%5Cfrac%7B-32%20%5Cpm%202%7D%7B2%7D%20%5C%5C%20%5C%5C%20Finally%2C%20%5C%20two%20%5C%20solutions%3A%20%5C%5C%20%5C%5C%20%5Cboxed%7Bx_%7B1%7D%3D-15%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7Bx_%7B2%7D%3D-17%7D)
<h2>Learn more:</h2>
Quadratic Equations: brainly.com/question/10278062
#LearnWithBrainly
Answer:
First option is the right choice. i.e. ![70\:\:and \:\:93](https://tex.z-dn.net/?f=70%5C%3A%5C%3Aand%20%5C%3A%5C%3A93)
Step-by-step explanation:
Boxplots: In its simplest form, the boxplot presents five sample statistics - the minimum, the lower quartile, the median, the upper quartile and the maximum - in a visual display. The box of the plot is a rectangle which encloses the middle half of the sample, with an end at each quartile. The length of the box is thus the interquartile range of the sample. The other dimension of the box does not represent anything in particular. A line is drawn across the box at the sample median. Whiskers sprout from the two ends of the box until they reach the sample maximum and minimum. The crossbar at the far end of each whisker is optional and its length signifies nothing. The diagram below shows a dotplot of a sample of 20 observations (actual sample values used in the display) together with a boxplot of the same data.
Answer:
C
Step-by-step explanation:
negatives 0(zero) positives
<-------------------------------l------------------------------->
Let x = price for each cake and y = price of each pie in dollars.
We can get two equations out of the data. One from the Friday set, the other from the Saturday set.
![Equation \ 1: 30x+20y=460](https://tex.z-dn.net/?f=Equation%20%5C%201%3A%2030x%2B20y%3D460)
![Equation \ 2: 30x+40y=620](https://tex.z-dn.net/?f=Equation%20%5C%202%3A%2030x%2B40y%3D620)
Then, we subtract both equations. The difference would be:
-20y = -160
y = -160 ÷ -20
y = $8
Finally, we substitute y to any of the equations. Suppose, we use equation 1:
30x + 20(8) = 460
30x = 460 - 160
30x = 300
x = 300 ÷ 30
x = $10
Therefore, the cost for each cake and pie is $10 and $8, respectively.