Answer:
can you insert a picture or other information to answer this pls
Step-by-step explanation:
Answer: The angle through which the pendulum travels = 
.
Step-by-step explanation:
Formula: Length of arc: 
, where r= radius ( in radians) , 
= central angle.
Given: Length of pendulum (radius) = 45 cm
Length of arc= 27.5 cm
Put these values in the formula, we get
In degrees ,
![\theta=\dfrac{11}{18}\times\dfrac{180}{\pi}=\dfrac{110\times7}{22} \ \ \ \ [\pi=\dfrac{22}{7}]](https://tex.z-dn.net/?f=%5Ctheta%3D%5Cdfrac%7B11%7D%7B18%7D%5Ctimes%5Cdfrac%7B180%7D%7B%5Cpi%7D%3D%5Cdfrac%7B110%5Ctimes7%7D%7B22%7D%20%5C%20%5C%20%5C%20%5C%20%20%20%20%5B%5Cpi%3D%5Cdfrac%7B22%7D%7B7%7D%5D)
Hence, the angle through which the pendulum travels = .
5 hours hun just divide and times and maybe you will find it
Answer:
|x-5|=2
Step-by-step explanation:
1- Find the mid value between the given numbers 3 and 7
(3+7)/2= 10/2 = 5
2- Find the difference btween the mid value (5) and any of the two given numbers (3 or 7). Use the absolute value for the difference.
|5-3|= 2 or |7-5|=2
3- Arrange the absolute equation like this:
|x-mid value from step 1|= absolute difference from step 2
|x-5|=2
4- Double check the answer with the given values 3 and 7 using our equation |x-5|=2
|3-5|=2 correct
|7-5|=2 correct
Using the properties of percentages we can calculate that there are 200 kids in the archery camp that summer.
Long before the decimal numeral system, Ancient Rome routinely computed in fractions as multiples of 1/100.
A percentage is a dimensionless (pure) number; it has no unit of measurement.
The % value is determined by multiplying the numerical value of the ratio by 100. To calculate 50 apples as a percentage of 1250 apples, first compute 50/1250 = 0.04, then multiply by 100 to get 4%.
Let the total number of kids in the camp be x.
The number of kids who took archery = 25%
But 50 students took archery.
hence 25% of x = 50
Solving we infer:
x = 200
Therefore there are 200 kids in the camp.
To learn more about percentages visit:
brainly.com/question/15840409
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