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sattari [20]
3 years ago
9

The diagram shows a food web , In the food web - ( I NEED HELP ASAP )

Biology
1 answer:
IgorLugansk [536]3 years ago
6 0
Krill, snails and abalones are primary consumers
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The initiating event in the development of nephrotic syndrome is a derangement in the glomerular membrane that causes increased
makkiz [27]

The initiating event in the development of nephrotic syndrome is a derangement in the glomerular membrane that causes increased permeability to plasma proteins.

Nephrotic syndrome can be understood as a kidney disorder in which the glomeruli filter of the kidney gets damaged due to which it is unable to filter the proteins and passes an excess amount of protein in the urine.

Glomeruli filter consists of clusters of small blood vessels in the kidneys that function in filtering the waste and excess water from the blood. It also sweeps the blood protein which is necessary to maintain the correct amount of fluid in the body, from seeping into the urine. But when it gets damaged glomeruli stop sweeping the protein from the urine as a result too much blood protein leaves your body, leading to nephrotic syndrome.

Learn more about Nephrotic syndrome here

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5 0
2 years ago
The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A
ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

<em><u>Genotype       Observed frequency</u></em>

    A             →        18 individuals

    B             →        55 individuals

    C             →        27 individuals

Do these contradict the genetic model?  

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.  

Explanation:

<u>Available data</u>:

  • Crossed genotypes: two
  • Genotypes among the offspring; Three → A, B, and C
  • Expected phenotypic ratio → 1:2:1
  • Total number of individuals, N = 100
  • A = 18 individuals
  • B = 55 individuals
  • C = 27 individuals

So, let us first state the hypothesis:

  • H₀= the population is equilibrium for this locus → F(A) = 25%,  F(B) = 50%, F(C) = 25%  
  • H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 ---------------  25% -------------X = 25 individuals A

2 --------------  50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

<u>                                                   A                             B                           C</u>

  • Observed                         18                            55                         27
  • Expected                         25                           50                         25
  • (Obs-Exp)²/Exp                1.96                        0.5                        0.16

<u>(Obs-Exp)²/Exp</u>

A)  (18 - 25)²/25 = 49/25 = 1.96

B)  (55 - 50)² / 50 = 25/50 = 0.5

C)  (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp  

  • ∑ is the sum of the terms
  • O are the Observed individuals: 2 in chamber B, and 18 in chamber A.  
  • E are the Expected individuals: 10 in each chamber  

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05  

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99    

<em>These results suggest that there is </em><u><em>not enough evidence to reject</em></u><em> the null hypothesis. We can assume that </em><u><em>the locus under study in this population is in equilibrium H-W.  </em></u>

 

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3 years ago
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Explanation:

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i think false because they can help with another animal and there population decrease
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cardiac, smooth, and skeletal.

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