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Katen [24]
3 years ago
10

I"LL GIVE 100 PTS PLEASE ANSWER THIS QUESTION

Mathematics
2 answers:
Talja [164]3 years ago
6 0

Answer:

6 grams of fat in a snack then 50 grams of protein in snacks write this

Step-by-step explanation:

ollegr [7]3 years ago
5 0

Answer:

6 grams of fat in a snack then 50 grams of protein in snacks

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While playing volleyball, Ralph drank 3/4 of a jug of water. If the jug held 64 fluid ounces of water, how much water did Ralph
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48

Step-by-step explanation:

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3 years ago
Use completing the square to solve the equation x^2 0 10x = 08.
wariber [46]
Ok so assuming the 0 means minus from typing problems

x^2-10x=-8

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make sure the term in front of x^2 is 1
that is correct
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answer is the first equation
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is -3 or 2 a higher slope? ( please help fast will give brainliest and thanks!!!!! 100 points help pleaseeeeee!!!!)
Tomtit [17]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

5 0
3 years ago
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