A polynomial function of least degree with integral coefficients that has the
given zeros
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
Now we multiply it to get the polynomial
polynomial function of least degree with integral coefficients that has the
given zeros
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Answer:
The y intercept should be 2 lower than the original equation
Step-by-step explanation:
Answer:
Answers provided below
Step-by-step explanation:
From the simultaneous linear equation, we have the coefficient matrix as;
(3 4 5)
(2 -1 8)
(5 -2 7)
The x-matrix is Dx is given by;
(18 4 5)
(13 -1 8)
(20 -2 7)
Similarly, the y-matrix Dy is given by;
(3 18 5)
(2 13 8)
(5 -20 7)
Also,the z-matrix Dz is given by;
(3 4 18)
(2 -1 13)
(5 -2 -20)
Determinant of the coefficient matrix from online determinant calculator is;
D = 136
Determinant of the x-matrix from online determinant calculator is; Dx = 92
Determinant of the y-matrix from online determinant calculator is; Dy = 696
Determinant of the z-matrix from online determinant calculator is; Dz = 576
From crammers rule;
x = Dx/D = 92/136
y = Dy/D = 696/136
z = Dz/D = 576/136
Answer:
8n^8
Step-by-step explanation:
n3*2*n5*4
=8*n8
8n^8
Answer:
Ur final grade will go down if you are looking for answers buddy! :)
Step-by-step explanation: