Answer:
If D = 0, then the quadratic equation has 1 solution x = − b/2a
Step-by-step explanation:
If we have a quadratic equation x² +3x-4= 0
Then the corresponding values of a= 1, b=3, c= -4
Finding the discriminant gives
D= b2 - 4ac.
D= 3²- 4(1) (-4)
D= 9 + 16
D= 25
Here a> 0
But if a< 0 e.g a= -1
D= b2 - 4ac.
D= 3²- 4(-1) (-4)
D= 9 - 16
D= -7
Here a < 0 so we get the answer -7 < 0
D= b2 - 4ac.
D= 4²- 4(-1) (-4)
D= 16 - 16
D= 0
Here a< 0 and b= - c so that D= 0
When D < 0 roots do not exist.
If D = 0, then the quadratic equation has 1 solution x = − b/2a
This can be found out by using the quadratic formula
x= -b±√b²- 4ac/ 2a
But D= 0
x= -b±0/ 2a
x= -b/2a
Answer:
2.5, -1.8
Step-by-step explanation:
½(x¹+x²) ,½(y¹+y²)
½(3.5+1.5) ,½(2.2+(-4.8)
½(5.0), ½(2.2-4.8)
2.5 ,½(-3.6)
2.5, -1.8
Not funny ^ :|... The answer would be the Gupta Empire..
Answer:
D. (2y - 7) units by (2y + 7) units
Step-by-step explanation:
- -> D(rectangle) = (2y-7) units by (2y + 7) units