The probability that Aiden randomly selects an oatmeal cookie from the bag, eats it, then randomly selects a chocolate chip cookie is 0.0721
<h3>How to determine the probability?</h3>
The distribution of the cookies is given as:
- 9 chocolate chip cookies
- 8 peanut butter cookies
- 8 sugar cookies
- 9 oatmeal cookies
When he eats a cookie, the number of cookies reduces by 1
So, the required probability is:
P(Oatmeal and Chocolate) = Oatmeal/Total * Chocolate/Total - 1
This gives
P(Oatmeal and Chocolate) = 9/(9 + 8 + 8 + 9) * 9/(9 + 8 + 8 + 9 -1)
Evaluate
P(Oatmeal and Chocolate) = 0.0721
Hence, the probability is 0.0721
Read more about probability at:
brainly.com/question/25870256
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I think you have to multiply across.
Answer:
9.8in
Step-by-step explanation:
i think this right
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X + 4/5 = 11
x = 11 - 4/5
x = 55/5 - 4/5
x = 51/5 or 10 1/5
or u can do it this way..
x + 4/5 = 11.....multiply everything by common denominator of 5
5x + 4 = 55
5x = 55 - 4
5x = 51
x = 51/5 or 10 1/5
