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4 years ago

PLEASE HELP

1 answer:

6 0

Formula: (y-y1/y2-y1 = x-x1/x2-x1)

For the line containing the points (-5,5) and (5,-5)

The Equation is 10x+10y=0

The Equation in point slope form for the line, of slope 3 and (-6,-1)
is 3x-y+17=0

an equation in point sloe form for the line containing the points (5,7) and (6,3) is 3x+2y=27

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A square pyramid has a height of 12 feet. Each side to of base is 7 feet long. use the following formula to calculate the pyrami

MissTica

Let's find the area of the base first:
7×7=49
The S stands for the sides of the base. Since you are multiplying them by each other, you are basically squaring them.

Let's now multiply the area of the base by the height.
49×12=588

Now, let's multiply by 1/3.
588×1/3 or 588÷3
196

So, the volume is 196 ft³.

4 0

3 years ago

This question is from the similarity chapter. It would be really kind of you if you would answer this question.

katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

1) Determine what is required for the answers

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

2) Prove similarity

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

Angles AYX and ACB are corresponding and they both measure 90 degrees
Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

3) Solve for part A

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

$\frac{XY}{BC}=\frac{AY}{AC}$

Plug in known values

$\frac{2}{300}=\frac{11}{AC}$

Cross-multiply

$2AC=11*300\\2AC=3300\\AC=1650$

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

4) Solve for part B

To find the length of AB, we can use the Pythagorean theorem:

$a^2+b^2=c^2$ where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

$300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c$

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0

3 years ago

How do you break this down percent proportion showing work withIs/of=%/100

bixtya [17]

20% of 56

Let the number be x

Solving

$\begin{gathered} \frac{x}{56}=\frac{20}{100} \\ \Rightarrow x=11.2 \end{gathered}$

The answer is 11.2.

6 0

1 year ago

Need help please don't know this

vesna_86 [32]

Perimeter = 2w + 2l
2(8x+2) + 2(6x + 6)
Use distributive property
16x + 4 + 12x + 12
Combine like terms
28x + 16

Solution: 28x + 16

3 0

3 years ago

Read 2 more answers

Equation of perpendicular line: Equation of parallel line:

tamaranim1 [39]

1)Parallel means they have to have the same slope. Since our equation is y=2/3x+1, a line parallel to that would be(using out points) -5=2/3(-4)+b.

To find the y-intercept, solve for "b".

b=-7/3

Our equation would then be y=2/3x-7/3

2)Perpendicular lines have opposite-reciprocal slopes. our previous equation was y=2/3x+1, so our new equation would be -5=-3/2(-4)+b. Now lets solve for b.

b=-11

So our perpendicular equation would be y=-3/2x-11

Hope that was helpful. :)

8 0

4 years ago