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3 years ago

How do I solve this problem? I don’t need the answer I just need to know how to solve it

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

6 0

hey i would love to help but wheres the question : )

anygoal [31]3 years ago

3 0

what problem do you need?

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Megan’s car averaged 336 miles on 12 gallons of gas. How many gallons of gas did Megan use to drive 1,344 miles on vacation? a.

aalyn [17]

Okay, so first divide 336 / 12 to find out how many miles are driven on each gallon. 336 / 12 = 28 So the car travels 28 miles per gallon (mpg).

Then, divide 1,344 / 28 1,344 / 28 = 48

And there's your answer! D) 48 gallons

5 0

3 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

Brooke paints the outsides of the square walls and triangular ceilings of her treehouse. What area does she paint? Enter your an

andrew-mc [135]

Answer:

216

Step-by-step explanation:

The formula of finding the surface is length * width * height or LxWxH.

Since everything is 6 you just multiply 6*6*6 which gives you 36*6 which gets you 216. You don't need the top 6 just to find the surface she will paint.

Hope this helps!

7 0

2 years ago

A.2.1<br> B.5<br> C.21.2<br> D.22.1

satela [25.4K]

The answer is D. 22.1.
Hope this helps!! Have a good Day!!! :D

8 0

2 years ago

Y=-1/3x +5 <br> Please thank u

PolarNik [594]

Ok this is a linear equation that is descending and is in slope intercept form

8 0

2 years ago