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erastovalidia [21]
3 years ago
11

Your answer should be an expanded polynomial in standard form.(-2k^3-7k^2+5k)+(6k^2+3k)​

Mathematics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

-2k^{3} -k^{2} +8k

Step-by-step explanation:

Just add like terms

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42 is what percent of 140
agasfer [191]


42 is 30% of 140

This is evident because, 42÷140=0.3

And you should hopefully know your place values right?

So then we know that 3 is in the10ths place and so to change the decimal to a fraction we get 3/10 which then changed to a percent, is equal to 30.

Long story short, 42 is 30% of 140 :)

4 0
3 years ago
Find the relative minimum of y = 3x^3 + 12x^2 - 10x - 56
Ilia_Sergeevich [38]

Answer:

(0.4, -57.9)

Step-by-step explanation:

y = 3x³ + 12x² - 10x - 56

dy/dx = 9x² + 24x - 10 = 0

x = [-24 +/- sqrt(24² - 4(9)(-10))]/(2×9)

x = -3.033006505, 0.3663398379

d²y/dx² = 18x + 24

For minima, d²y/dx² > 0 which is at x = 0.3663398379

y = 3(0.3663398379)³ + 12(0.3663398379)² - 10(0.3663398379) - 56

y = -57.90544608

7 0
3 years ago
Fined the measure of arc NL
adelina 88 [10]
The measure of an arc is twice the measure of the inscribed angle that intercepts it.

m(arc)NL = 2 * 42 = 84
5 0
3 years ago
In the following figure, select whether the green and red graphics are functions or not
ExtremeBDS [4]

Answer:

  C. green is not a function, red is a function

Step-by-step explanation:

A curve does not describe a functional relationship if a vertical line crosses it in more than one place. Clearly the y-axis crosses the green curve in 2 places, so it is NOT a function.

There is a very steep section at x=10 on the red curve. It we assume it is simply "very steep" and not "vertical", then the red curve IS a function. If you assume that short section is vertical, then the red curve is not a function, either. My choice is to go with "very steep," not "vertical."

My conclusion is that green is not a function; red is a function.

5 0
3 years ago
What is the gradient of the graph shown?
sladkih [1.3K]

Answer:

gradient = \frac{1}{3}

Step-by-step explanation:

calculate the gradient m using the gradient formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 6, 0) and (x₂, y₂ ) = (0, 2) ← 2 points on the line

m = \frac{2-0}{0-(-6)} = \frac{2}{0+6} = \frac{2}{6} = \frac{1}{3}

3 0
2 years ago
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