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kozerog [31]
3 years ago
11

10 points and will mark brainliest!

SAT
1 answer:
CaHeK987 [17]3 years ago
3 0

A, B, B, A, B, A

Hope this helps.

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Mai is making personal pizzas. For 4 pizzas, she uses 10 ounces of cheese. Consider using a table to help answer the questions b
Step2247 [10]

Based on the amount of cheese used for the pizzas, the following are true:

  • a. Mai uses 2.5 ounces of cheese per pizza.
  • b. Mai will need 37.5 ounces for 15 pizzas.

<h3>Cheese used per Pizza. </h3>

This can be found as:

= Ounces of cheese used / Number of pizzas

= 10 / 4

= 2.5 ounces per pizza.

<h3 /><h3>Cheese needed for 15 pizzas. </h3>

= Number of pizzas x Cheese per pizza

= 15 x 2.5

= 37.5 ounces of cheese.

In conclusion, Mai needs 37.5 ounces of cheese to make 15 pizzas.

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Satya, nina, and iana each have a 3/4 chance of going to café georgia for an afternoon coffee at 1:00pm. Bohan will only go to c
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Using the binomial distribution, it is found that there is a 0.9844 = 98.44% probability that bohan goes to café georgia for a coffee today.

For each friend, there are only two possible outcomes, either they go to the cafe, or they do not. The probability of a friend going to the cafe is independent of any other friend, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 3 friends, hence n = 3.
  • They all go to the cafe with a 3/4 probability, hence p = 3/4 = 0.75.

The probability at least one goes is:

P(X \geq 1) = 1 - P(X = 0)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.75)^{0}.(0.25)^{3} = 0.0156

Then:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0156 = 0.9844

0.9844 = 98.44% probability that bohan goes to café georgia for a coffee today.

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