Answer:
the answer is 2304
Step-by-step explanation:
8×8=64
64×36=2304
You just put the numbers on the number line and count the integers between them.
However, the formula for difference = (big number) - (small number)
Therefore,
41 - (-23)
= 41 + 23
= 64
So the difference is 64.
Answer:
![x^2-100=(x-10)(x+10)](https://tex.z-dn.net/?f=x%5E2-100%3D%28x-10%29%28x%2B10%29)
Explanation:
Given the expression:
![x^2-100](https://tex.z-dn.net/?f=x%5E2-100)
This can be a difference of two squares like:
![x^2-10^2](https://tex.z-dn.net/?f=x%5E2-10%5E2)
and this is:
Answer:
Option D.
Step-by-step explanation:
Consider the given expressions are
![14^2\times 12^2\times 12^1](https://tex.z-dn.net/?f=14%5E2%5Ctimes%2012%5E2%5Ctimes%2012%5E1)
![14^2\times 12^3](https://tex.z-dn.net/?f=14%5E2%5Ctimes%2012%5E3)
![14\times 14\times 12\times 12\times 12](https://tex.z-dn.net/?f=14%5Ctimes%2014%5Ctimes%2012%5Ctimes%2012%5Ctimes%2012)
![14^1\times 14^1\times 12^2+12^1](https://tex.z-dn.net/?f=14%5E1%5Ctimes%2014%5E1%5Ctimes%2012%5E2%2B12%5E1)
On solving these expression we get
![14^2\times 12^2\times 12^1=14\times 14\times 12\times 12\times 12=338688](https://tex.z-dn.net/?f=14%5E2%5Ctimes%2012%5E2%5Ctimes%2012%5E1%3D14%5Ctimes%2014%5Ctimes%2012%5Ctimes%2012%5Ctimes%2012%3D338688)
![14^2\times 12^3=14\times 14\times 12\times 12\times 12=338688](https://tex.z-dn.net/?f=14%5E2%5Ctimes%2012%5E3%3D14%5Ctimes%2014%5Ctimes%2012%5Ctimes%2012%5Ctimes%2012%3D338688)
![14\times 14\times 12\times 12\times 12=338688](https://tex.z-dn.net/?f=14%5Ctimes%2014%5Ctimes%2012%5Ctimes%2012%5Ctimes%2012%3D338688)
![14^1\times 14^1\times 12^2=14\times 14\times 12\times 12+12=28236](https://tex.z-dn.net/?f=14%5E1%5Ctimes%2014%5E1%5Ctimes%2012%5E2%3D14%5Ctimes%2014%5Ctimes%2012%5Ctimes%2012%2B12%3D28236)
First three expressions are equivalent and fourth expression is not equivalent to others.
Therefore, the correct option is D.