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Allisa [31]
3 years ago
5

Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.36 kW/m 2 . How long does it take for 2.

55 × 10 9 J to arrive on an area of 4.75 m 2 ?
Geography
1 answer:
Tresset [83]3 years ago
5 0

Answer:

Time =   3.947 × 10^{5} s

Explanation:

given data

intensity =  1.36 kW/m²

energy = 2.55 × 10^{9}  J

area = 4.75 m²

solution

as energy is express as

Energy E = PT

here P is intensity and T is time

and here after some time power of radiation deliver is delivering on area that is

E = P*AT

so T = \frac{E}{p*A}   ...............1

put here value

T = \frac{2.55*10^9}{1.36*10^3*4.75}    

T =   3.947 × 10^{5} s

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