Question

Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.36 kW/m 2 . How long does it take for 2.55 × 10 9 J to arrive on an area of 4.75 m 2 ?

Answer 1

Answer:

Time =   3.947 × $10^{5}$ s

Explanation:

given data

intensity =  1.36 kW/m²

energy = 2.55 × $10^{9}$  J

area = 4.75 m²

solution

as energy is express as

Energy E = PT

here P is intensity and T is time

and here after some time power of radiation deliver is delivering on area that is

E = P*AT

so T = $\frac{E}{p*A}$   ...............1

put here value

T = $\frac{2.55*10^9}{1.36*10^3*4.75}$    

T =   3.947 × $10^{5}$ s