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3 years ago

How to write 863.141 in expanded form

Mathematics

1 answer:

Sav [38]3 years ago

5 0

800+60+3+0.10+0.040+0.001

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There is a group of 5 turtles near the playground. More turtles joined. Now there are 13 turtles. How many turtles joined the gr

ivann1987 [24]

Answer:

8 turtles joined the group

Step-by-step explanation:

13-5=8

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3 years ago

Problem of the Week

Ierofanga [76]

Answer:

CD is 6 cm and DE is 4 cm.

Step-by-step explanation:

Well it‘s the correct answer and I got it right so good luck out there bois!

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

SOLVE FOR X<br><br> -5x + 9 = 24

boyakko [2]

Answer:

Step-by-step explanation:

-5x + 9 = 24

move the nine to the other side

-5x = 15

divide

x = -3

7 0

3 years ago

Say that you leave montevideo at 6:20 p.m. on sunday to fly to jerusalem. when you arrive in jerusalem, the local time is 10:00

iragen [17]

Its A. Five hours ahead :)

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3 years ago

Read 2 more answers