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vovikov84 [41]
3 years ago
15

What is the solution to this question b-1= 1+b

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer: The answer would be no solution.

Step-by-step explanation: The variable b has to equal the same on both sides, therefore if one was to add one to one side and subtract one from the other, it would become unbalanced.

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Which decimal is equal to four-fifths? 0.6 0.8 0.2 0.3 0.4
DochEvi [55]
4/5 = 80/100

0.8 = 80/100

4/5 = 0.8

hope this helps
4 0
3 years ago
Help pleaseeeeee am kinda stuck ​
aleksley [76]

Answer:

{ \tt{- \frac{3}{6} \:  \:  \:  \frac{9}{15}   \:  \:  \frac{10}{25}  \:  \:  \frac{24}{30} \:  \: 7 }} \\

7 0
2 years ago
7-5(2x+14)= -2(x+63)
jeka94

7-5(2x+14)= -2(x+63)

7 - 10x - 70 = -2x - 126

-10x - 63 = -2x - 126

You finish.

6 0
3 years ago
Jose measured a small granola bar in the shape of a rectagular prism. It was 5 mm tall, 50 mm long, and 30 mm wide. He stacked t
Daniel [21]

Answer:

15,000 mm^3

Step-by-step explanation:

volume of the 2 stacked granola bars = volume of one granola bar x 2

volume of one granola bar = Volume of a prism = base area x height

5 x 55 x 30 x 2 = 15,000

8 0
3 years ago
Water weighs 62.4 pounds per cubic foot. How much does the water in a tank that measures 7 ft × 4 ft × 9 in, weigh?
andriy [413]

Answer:

  • <u>1,310 lb</u>

Explanation:

<u>1) Calculate the volume of the water in the tank.</u>

  • Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
  • Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
  • Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.

<u>2) Calculate the weight of 21 ft³ of water.</u>

Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:

  • 62.4 lb / 1 ft³ = x / 21 ft³

Solve for x:

  • x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.

So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.

6 0
3 years ago
Read 2 more answers
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