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Fantom [35]
3 years ago
12

Taxi ride is 1.85 per mile with an initial 2.75 charge, what is the cost in dollars for a 20 mile taxi ride

Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:$39.75

First, we have to find out how much would it be for a 20 mile taxi ride. To do this, we have to multiply. 20 x $1.85= $37.00.

Lastly, you have to find out how much the cost will be with the initial charge. To do this, we have to add. $37.00+$2.75=$39.75.

Hope this answered your question!

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Answer:

A yes

B  yes

C  No

D  No

Step-by-step explanation:

If it is a function then the first number in the ordered pair is use only one time.

5 0
2 years ago
Express your final answer in simplest form 3/5 + -7/8
frez [133]

Answer:

- 0.5

Step-by-step explanation:

you first change the fractions numbers  in to decimal form

      so;   2/5 = 0.4

               -7/8 = - 0.875

hence;   0.4 + (-0.875)

             = - 0.475

in to its simplest form   =  - 0.5

  the answer is - 0.5

5 0
3 years ago
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Veronika [31]
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2 years ago
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According to a survery 52% of the residents of a city oppose a downtown casino. Of these 52% about 5 out of 10 strongly oppose t
nignag [31]
<span>I need to satert by stating the questions clearly. Question A: What is the probability that a radomly selected resident opposes the casino and strongly opposes the casino? This is the joint probability of being opposed and being strongly opposes which is calculated as the product of both: 52/100 * 5/10 = 26/100 = 0.26. Question B. What tis the probability that a radomly selected resident opposes the casino and does not strongly oppose the casino. Again it is a joint probability, the product of being opposed and not being strongly opposed: 52/100 * 5/10 = 26/100 = 0.26. The are the same because the the half of the 52% oppose strongly and the other half does not. </span>
8 0
3 years ago
Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of
Shalnov [3]

Answer:

Owl= 67.14ft

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}

22^{\circ} 8'6'' = 22.135^{\circ}

30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}

30^{\circ} 40'30'' = 30.675^{\circ}

Considering Jason's position:

tan(22.135^{\circ}) = \frac{H}{x + 48}

Where x = distance between the tree and Alison

Make H the subject

H = (x + 48)tan(22.135^{\circ})

Considering Alison's position

tan(30.675^{\circ}) = \frac{H}{x}

Make H the subject

H = xtan(30.675^{\circ})

H = H

(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})

(x + 48) *0.4068 = x* 0.5932

Open bracket

x *0.4068 + 48 *0.4068 = 0.5932x

0.4068x + 19.5264 = 0.5932x

Collect Like Terms

-0.5932x+0.4068x = -19.5264

-0.1864x = -19.5264

0.1864x = 19.5264

Make x the subject

x = \frac{19.5264}{0.1864}

x = 104.76

Substitute 104.76 for x in H = xtan(30.675^{\circ})

H = 104.76 * tan(30.675^{\circ})

H = 104.76 * 0.5932

H = 62.14

The above represents the height of the tree.

The height of the owl is:

Owl= H + 5

Owl= 62.14 + 5

Owl= 67.14ft

7 0
2 years ago
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