The amount to be invested today so as to have $12,500 in 12 years is $6,480.37.
The amount that would be in my account in 13 years is $44,707.37.
The amount I need to deposit now is $546.64.
<h3>How much should be invested today?</h3>
The amount to be invested today = future value / (1 + r)^nm
Where:
- r = interest rate = 5.5 / 365 = 0.015%
- m = number of compounding = 365
- n = number of years = 12
12500 / (1.00015)^(12 x 365) = $6,480.37
<h3>What is the future value of the account at the end of 13 years?</h3>
Future value = monthly deposits x annuity factor
Annuity factor = {[(1+r)^n] - 1} / r
Where:
- r = interest rate = 5.3 / 12 = 0.44%
- n = 13 x 12 = 156
200 x [{(1.0044^156) - 1} / 0.0044] = $44,707.37
<h3>What should be the monthly deposit?</h3>
Monthly deposit = future value / annuity factor
Annuity factor = {[(1+r)^n] - 1} / r
Where:
- r = 6.7 / 12 = 0.56%
- n = 2 x 12 = 24
$14,000 / [{(1.0056^24) - 1} / 0.0056] = $546.64
To learn more about annuities, please check: brainly.com/question/24108530
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First, make it into slope intercept form. Subtract x form both sides
x (-x) - y = 5 (-x)
-y = -x + 5
Isolate the y. Divide -1 from both sides
(-y)/-1 = (-x + 5)/-1
y = x - 5
The slope in the form: y = mx + b, is m, which is next to the x
In this case, the m is 1
You're slope is 1
hope this helps
