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Veseljchak [2.6K]
3 years ago
15

A. B. C. D. ????????????

Mathematics
1 answer:
qaws [65]3 years ago
4 0

n^{16} and 9 are the squares of, respectively, n^8 and 3.

So, using

a^2-b^2=(a+b)(a-b)

we have

n^{16}-9=(n^8+3)(n^8-3)

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