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3 years ago

Samara ate 1/3 of a pizza and Vyolet ate 1/5 of the pizza. How much of the pizza did they eat in all?

Mathematics

1 answer:

jeka57 [31]3 years ago

7 0

All together, the two girls ate 8/15 of a pizza. you mulitply your fractions out of equal denominaters and get that.

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Eli is a loan officer. He determines his clients’ eligibility for loans and for good interest rates by using their credit scores

Marianna [84]

Answer:

your answer is D.

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

a cooler contains 50 bottles; 30 bottles of water, which 8 are lemon flavored and 20 bottles of tea, of which 5 are lemon flavor

xenn [34]

Answer:

The required probability is $\dfrac{13}{50}$

Step-by-step explanation:

Total number of bottles = 50

Total number of water bottles = 30

Total number of lemon flavored water bottles = 8

Total number of tea bottles = 20

Total number of lemon flavored tea bottles = 5

Probability of selecting a lemon flavored water bottle = Probability of selecting a water bottle $\times$ Probability of selecting a lemon bottle out of water bottles.

Probability of selecting a lemon flavored tea bottle = Probability of selecting a tea bottle $\times$ Probability of selecting a lemon bottle out of tea bottles.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Probability of selecting a water bottle:

$\dfrac{30}{50} = \dfrac{3}{5}$

Probability of selecting a lemon flavored bottle from water bottle:

$\dfrac{8}{30}$

Probability of selecting a lemon flavored water bottle = P(A)

$\dfrac{3}{5} \times \dfrac{8}{30} = \dfrac{4}{25}$

Probability of selecting a tea bottle:

$\dfrac{20}{50} = \dfrac{2}{5}$

Probability of selecting a lemon flavored bottle from tea bottle:

$\dfrac{5}{20} = \dfrac{1}{4}$

Probability of selecting a lemon flavored tea bottle = P(B)

$\dfrac{2}{5} \times \dfrac{1}{4} = \dfrac{1}{10}$

The required probability is:

P(A) + P(B):

$\dfrac{4}{25} + \dfrac{1}{10}\\\Rightarrow \dfrac{8+5}{50}\\\Rightarrow \dfrac{13}{50}$

8 0

4 years ago

What is the answer to 1/4 + 8 * 8 + 6 + 8

dsp73

If you turn 1/4 into a decimal, which is 0.25, all you have to do then is 0.25 + 8 x 8 + 6 + 8 = 78.25 Hope this helps!!

8 0

3 years ago

Simplify, state all restrictions.

Kipish [7]

The simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1$

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

$\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Rewrite the expression as products

$\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Cancel out the common factors

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1$

Express 4x^2 - y^2 as (2x - y)(2x + y)

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1$

Cancel out the common factors

$\frac{1}{x + y} -1$

Take the LCM

$\frac{1 - x - y}{x + y}$

Hence, the simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$