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VARVARA [1.3K]
4 years ago
8

jordans dog weighs pounds emmett's dog weighs 25% more than.jordan's.dog which expressions represent the weight in of emmett's d

og? a.0.25p b.1.25p c. p + 0.25 d. p + 1.25 e. p + 0.25p
Mathematics
2 answers:
ira [324]4 years ago
4 0
E. p + 0.25p best represents the weight of Emmett's dog The total weight of Jordan's dog is represented as P. The weight of Emmett's dog is equal to the weight of Jordan's dog but with an additional fraction of the weight of Jordan's dog. The additional fraction is 25% or 1/4 of the weight of Jordan's dog.
Lady_Fox [76]4 years ago
3 0

Answer:

the expression fir the weight  of Emmett's dog is 1.25p

Step-by-step explanation:

The weight of Jordan's dog is p pounds.

And it has been given that Emmett's dog weighs 25% more than Jordan's dog.

Hence, 25% of weight of Jordan's dog is

25% of p

= 0.25p

Now, since, Emmett's dog weighs 25% more than Jordan's dog.

Hence, the weight  of Emmett's dog is given by

Weight of  Jordan's dog + 25% of weight of Jordan's dog

= p + 0.25p

=1.25 p

Therefore, the expression fir the weight  of Emmett's dog is 1.25p

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Sholpan [36]

ANSWER

The exact value is 24√3

The approximate value is 41.6 to the nearest tenth.

x=52.1 units.

EXPLANATION

Let the blue dotted line be h units.

This line is opposite to the 60° angle.

The side length of the triangle which is 24 units is adjacent to the 60° angle.

So we use the tangent ratio,

\tan(60 \degree)  =  \frac{opposite}{adjacent}

\tan(60 \degree)  =  \frac{h}{24}

\sqrt{3} =  \frac{h}{24}

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This is the exact value.

h = 41.6

This is that approximate value to the nearest tenth.

To find the side length , x, we need to use the second triangle.

\sin(53\degree)  =  \frac{h}{x}

\sin(53\degree)  =  \frac{41.6}{x}

x =  \frac{41.6}{\sin(53\degree)}

x = 52.1

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Step-by-step explanation:

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