Question

Question 2c of 40

Answer 1

Answer:

C. $-27+10i$

Step-by-step explanation:

The expression is:

$(i+3)+6i-3(8-i)$

Distribute -3 inside the bracket. This gives,

$i+3+6i+(-3\times 8)- (-3\times i)\\ i+3+6i-24-(-3i)\\ i+3+6i-24+3i$

Now, we combine the like terms and simplify. This gives,

$(i+6i+3i)+(-24-3)=10i+(-27)=-27+10i$

Therefore, $(i+3)+6i-3(8-i)$ is equal to $-27+10i$.